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tino4ka555 [31]
3 years ago
9

Find the range of the graphed function.

Mathematics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

The range of the function should be:

-9 ≤ y ≤ 5

Hence, option D is true.

Step-by-step explanation:

We know that the set of values of the dependent variable for which a function is defined.

From the given function, we can easily observe that the graph is kind of oscillating between the y-value y = 5 and y = -9.

i.e.

at y = 5, the graph gets its maximum value

at y = -9, the graph gets its minimum value

Thus, the range of the function should be:

-9 ≤ y ≤ 5

Hence, option D is true.

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Ali currently has $25. He is going to start saving $5 every week. Ali's Savings Function Rule: y = 5x + 25
makvit [3.9K]

Answer:

x-intercept: (-5,0)

y-intercept (0,25)

or in standard form 5x - y = -25

Step-by-step explanation:

8 0
3 years ago
Help me please, I’m still struggling with y intercepts, rates of change, etc.
BaLLatris [955]

Answer:

(a) The y-intercepts of both functions are the same, 0.  However, the rate of change for the school library is 0.25, while the rate of change for the city library is 0.35.  

(b) The 3-day late fee at the school library is $0.75 and the 3-day late fee at the city library is $1.05.

Step-by-step explanation:

The functions represented in the question are linear, which means that they have a consistent rate of change over time.  In this example, it means that for every day, the late fee charged by each library is the same.  At the school library, the rate of change is 0.25, which means for each day the book is late, the school charges a fee of $0.25.  At the city library, the table shows that for each day the book is late, the city charges a fee of $0.35.  So, the city library is more expensive.  Y-intercept refers to the initial cost, or how much do the libraries charge if the book is not late, or turned in on time.  In this case, neither library charges a fee for books turned in on time, so both would have a y-intercept of 0.  

5 0
4 years ago
If g(x) = X² +3, find g(4)
elena55 [62]

Answer:

g(4) = 19

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = x² + 3

g(4) is x = 4

<u>Step 2: Solve</u>

  1. Substitute:                    g(4) = 4² + 3
  2. Evaluate:                       g(4) = 16 + 3
  3. Add:                              g(4) = 19
3 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through (6, 3) and (3, 2).
hjlf

Answer:

1/3

Step-by-step explanation:

Slope m = (y2-y1)/(x2-x1)

m = (2 - 3)/(3 - 6) = (-1)/(-3) = 1/3

8 0
3 years ago
Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c
Elina [12.6K]

Answer:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

Step-by-step explanation:

Data given

n_1 =8 represent the sample size for group Boston

n_2 =9 represent the sample size for group Dallas

\bar X_1 =47 represent the sample mean for the group Boston

\bar X_2 =44 represent the sample mean for the group Dallas

s_1=3 represent the sample standard deviation for group Boston

s_2=3 represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

\sigma^2_1 =\sigma^2_2 =\sigma^2

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

The statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t student distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

Replacing we got:

\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9

And the deviation would be just the square root of the variance:

S_p=3

The statitsic would be:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

5 0
4 years ago
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