Question

A construction worker drops a hammer from 25m. How long will it take for the hammer to hit the ground? H(t)= -4.9t^2 +v +h

Answer 1

Answer:

the time taken for the hammer to hit the ground is 2.26 s.

Step-by-step explanation:

Given;

height through which the hammer falls, h = 25 m

The time taken for the hammer to hit the ground is calculated as;

$h(t) = ut + \frac{1}{2} gt^2\\\\h(t) = 0 + \frac{1}{2} (9.8)t^2\\\\h(t) = 4.9t^2\\\\t = \sqrt{\frac{h(t)}{4.9} } \\\\t = \sqrt{\frac{25}{4.9} } \\\\t = 2.26 \ s$

Therefore, the time taken for the hammer to hit the ground is 2.26 s.