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3 years ago

Determine the sum of the areas of the three triangles shown above.

Mathematics

1 answer:

N76 [4]3 years ago

6 0

I will be there at the same time I don't hear

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A rectangle prism has a square base of 12 inches and a height of 7 inches. What is the volume of the prism?

Natali [406]

1,008 is the answer I got

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3 years ago

Which of these sequences is a geometric sequence?

podryga [215]

3, 9, 27, 81, 343, 729, … is a geometric sequence because each term is obtained by multiplying 3 to the preceding term.

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2 years ago

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HELP ME PLLLLZ dis is PEMDAS

hram777 [196]

Answer:

Give Branliest PLz

Answer is 15

Step-by-step explanation:

Half of 40 is 20 cause 40/2=20

Five less than 20 is 20-5 which= 15

So ur answer is 15

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3 years ago

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How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%

blondinia [14]

The trick is to exploit the difference of squares formula,

$a^2-b^2=(a-b)(a+b)$

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

$(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2$

Whatever you do to the denominator, you have to do to the numerator too. So

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2$

Expand the numerator:

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}$

So we have

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2$

But √12 = √(3•4) = 2√3, so

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}$

7 0

2 years ago

One study found that the number of interest groups increased by what percentage between 1959 and 1995?

FrozenT [24]

Answer:

Percentage change in interest groups between 1959 (500) & 1995 (600) = 20%

Step-by-step explanation:

Percentage change = <u>Change ie (New - Old) </u> x 100

Old value

Suppose -

Number of interest groups in 1959 = 500

Number of interest groups in 1995 = 600

Percentage change = [ (600 - 500) / 500 ] x 100

( 100 / 500 ) x 100 = 20%

6 0

3 years ago