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aivan3 [116]
3 years ago
7

A+a-ay+3y+4?????????

Mathematics
2 answers:
Lemur [1.5K]3 years ago
7 0


a+2y+4 is the answer


Ganezh [65]3 years ago
5 0
A + a - ay + 3y + 4
2a - ay + 3y + 4
2a + (-a + 3)y + 4
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How does the value of the 8 in 589,310 compare to the value of the 8 in 598,301?
zloy xaker [14]
589, 310

The 8 value is in the 10,000s place.

598, 301

The 8 is in the 1000s place.

So the difference of 10,000 over 1000 is 10

So your answer is B
6 0
2 years ago
Write the word sentence as an inequality<br> A number y divided by 6 is no more than 2
Sedbober [7]

Answer:

Y/6 <_ 2

Step-by-step explanation:

(Less than it equal to sign)

8 0
2 years ago
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
Arada [10]

Answer:

The number of bacteria at initial = 187

Step-by-step explanation:

Given that the population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t.

\frac{dN}{dt} = k N

\frac{dN}{N}  = k dt

Integrating both side we get

㏑ N = k t + C ------- (1)

Now given that after 3 hours it is observed that 500 bacteria are present and after 10 hours 5000 bacteria are present.

⇒ ㏑ 500 = 3 k + C -------- (2)

⇒ ㏑ 5000 = 10 k + C ------ (3)

⇒ ㏑ 5000 -  ㏑ 500 = 7 k

⇒ ㏑\frac{5000}{500} = 7 k

⇒  ㏑ 10 = 7 k

⇒ k = 0.329

Put this value of k in equation (2),

⇒ ㏑ 500 = 3 × 0.329 + C

⇒ C = 5.23

Put this value of C in equation 1 we get,

⇒ ㏑ N = k t + 5.23

Initially when t = 0 , then

⇒ ㏑ N = 5.23

⇒ N =  187

Thus the number of bacteria at initial = 187

8 0
3 years ago
stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
Anon25 [30]

Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

Hence The total number of ducks and swans in the lake after n months is

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
1 year ago
Help!! Only one attempt left!
Arturiano [62]

Answer:

The answer is none of the above

Step-by-step explanation:

FJ is the angle bisector of angle F

3 0
3 years ago
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