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denpristay [2]
2 years ago
9

Pls answer question 1-4 Ill give extra 100 points

Mathematics
1 answer:
Vlad1618 [11]2 years ago
3 0
I can’t really see the image I don’t know if it’s my internet but I’ll tell you the answer when it loads
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Total consumption of fruit juice in a particular country in 2006 was about 1.86 billion
hram777 [196]

Answer:

Step-by-step explanation:

Kindly check explanation

Step-by-step explanation:

The population of that country in 2006 was 500 million. What was the average number of

gallons of fruit juice consumed per person in the country in 2006? Use pencil and paper. Using the per

person amount from this problem, about how many gallons would your class consume?

Total consumption in 2006 = 2.11 billion gallons (2,110,000,000)

Population of country in 2006 = 500,000,000

Average number of gallons of fruit juice consumed per person in the country in 2006:

Total consumption / total population

2,110,000,000 / 500,000,000

= 4.22 gallons per person

Number of gallons class will consume :

Assume number of students in class = 15

Hence, class consumption equals:

Average consumption per person × number of students in class :

4.22 × 15 = 63.3 gallons

3 0
2 years ago
X2-2xy+y2=30 solve the equation
Rom4ik [11]

Answer:

2.1

Step-by-step explanation:

3 0
3 years ago
suppose that the population of a deer in state is 1500 and is growing 2% each year. predict the population after 4 years
aleksklad [387]
1500*2%=30
30*4=120
1500+120+1720
1720 deer in 4 years
4 0
3 years ago
Identify the "inside function" u = f(x) and the "outside function" y = g(u). Then find dy/dx using the Chain Rule.
skad [1K]
DfLet f(x)=\sec x and g(x)=\sqrt x. Then

y=\sec\sqrt x=\sec(g(x))=f(g(x))=f\circ g(x)

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}

where u=g(x)=\sqrt x, so that y=f(g(x))=f(u)=\sec u. We have

\dfrac{\mathrm du}{\mathrm dx}=\dfrac1{2\sqrt x}
\dfrac{\mathrm d\sec u}{\mathrm du}=\sec u\tan u

and so

\dfrac{\mathrm dy}{\mathrm dx}=\sec u\tan u\dfrac{\mathrm dy}{\mathrm du}=\dfrac{\sec\sqrt x\,\tan\sqrt x}{2\sqrt x}
5 0
3 years ago
Y
Arada [10]
What is this?????????
5 0
3 years ago
Read 2 more answers
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