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Varvara68 [4.7K]
3 years ago
9

What is the range and domain of this graph?

Mathematics
1 answer:
DochEvi [55]3 years ago
7 0

Answer:

Range: (-∞,∞)

Domain: (-∞,∞)

Step-by-step explanation:

Remember that if there are arrows that the function continues.

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The Walt Disney Company paid a $0.35 annual dividend on a day it closed at a price of
Dennis_Churaev [7]

Answer:\

hey check out the attachment i found them online hope it help and thank you!

I looked for them like for 20 min I finnaly found them

Have a nice day/night! LOL

Step-by-step explanation:

3 0
2 years ago
A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
Daniel borrowed $8,000 at 6% interest for 10 years. What was the total interest?   A. $48,000   B. $4,800   C. $480   D. $48
Mariulka [41]
I think it wold be b

please tell me if i wrong
4 0
2 years ago
Solve by substitution: <br> 2x-y = -5<br> -x+-y =10
Elenna [48]
2x-y=-5
-x-y=10
3x=-15
x=-5
-10-y=-5
-y=-5+10
-y=5
y=-5
HOPE I HELPED!!!
6 0
3 years ago
Read 2 more answers
A study is done by a community group in two neighboring colleges to determine which one graduate's students with more math class
ozzi

Answer:

thats a long question my friend

Step-by-step explanation:

7 0
3 years ago
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