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2 years ago

Find the derivative of the function given by f(x)=(√(x^2+1))/x

Mathematics

1 answer:

True [87]2 years ago

7 0

Answer:

Find the derivative of the function given by f(x)=(√(x^2+1))/x

Step-by-step explanation:

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108 is 36% of what number? Write and solve a proportion to solve the problem

kolezko [41]

Let the number = x

Then, it would be: (x*36)/100 = 108

x*36 = 10800

x = 10800/36

x = 300

3 0

3 years ago

For what integer value of x is 3x+5>11 and x-3 <1?

Andre45 [30]

3x + 5 > 11
3x + (5 - 5) > 11 - 5
3x > 6
3x / 3 > 6 / 3
x > 2

x - 3 < 1
x (-3 + 3) < 1 + 3
x < 4

When subtracting / adding values to both sides, the inequality does not change.

When multiplying / dividing by a positive value, the inequality also doesn't change, but when multiplying , dividing with a negative value, the inequality must be flipped.

7 0

3 years ago

Find the area of the following shape, given its curves are made from parts of circles with diameters indicated on the diagram.

Alexxandr [17]

Answer:

222.51 (when rounded)

Step-by-step explanation:

Pi x r squared is the formula to find the area of a circle

153.94 + 12.57 + 56

= 222.51

You basically find the area of each circle by find their diameters. So half of the length shown on each circle.

7 0

2 years ago

There are 1800 students in a school this number is 20% more than what they had last year find the number of students in the scho

harkovskaia [24]

I believe the number of students they had last year are 360 students i hope this helps.

5 0

3 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

2 years ago