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Vera_Pavlovna [14]
3 years ago
10

A number, x, rounded to 1 decimal place is 3.7 Write down the error interval for x.

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

The error in rounding a number is half of the unit of measure. The number was rounded to the nearest 0.1 unit so the error is half of 0.1 which is 12⋅0.1=0.05  

2

1

​  

⋅0.1=0.05. Since 3.7+0.05=3.753.7+0.05=3.75 and 3.7−0.05=3.653.7−0.05=3.65, then the error interval is \boxed{3.65\le x<3.75}.

Step-by-step explanation:

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a middle school has 520 students, 75% of the students ride the bus to school. How many students do not ride the bus to school?
Nata [24]

Answer:

130 students do not ride the bus to school.

Step-by-step explanation:

520 * .75 = 390

390 students ride the bus to school.

520-390=130

130 students do NOT ride the bus to school.

Hope this helps! :)

6 0
3 years ago
What is the degree measure of an angle that measures 4.5 radians​
Rzqust [24]

Answer:

257.8°

Step-by-step explanation:

rad × 180/π =  °

4.5*180=810

810/π=257.8

5 0
3 years ago
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Find the slope and y-intercept of the line. ​
sergey [27]

slope-intercept formula: y = mx + b

m = slope

b = y-intercept

your equation: y = 4/3x - 3

m = 4/3

b = -3

so, the answer would be the last option.

hope this helps, have a great day/night :)

4 0
3 years ago
If tan 0=3/4 find sin0
bija089 [108]

Answer:

sin O = \frac{3}{5}

Step-by-step explanation:

given tan O = \frac{3}{4} = \frac{opposite}{adjacent}

Then this is a right triangle with legs 3 and 4

Using Pythagoras' identity then the hypotenuse (h ) is

h = \sqrt{3^2+4^2} = \sqrt{25} = 5, hence

sin O = \frac{opposite}{hypotenuse} = \frac{3}{5}

6 0
3 years ago
Should i use dy\dx (normal differentiation) or d²y\dx² (differentiation of the differentiation)?​
11111nata11111 [884]

Use both!

You want to minimize <em>P</em>, so differentiate <em>P</em> with respect to <em>x</em> and set the derivative equal to 0 and solve for any critical points.

<em>P</em> = 8/<em>x</em> + 2<em>x</em>

d<em>P</em>/d<em>x</em> = -8/<em>x</em>² + 2 = 0

8/<em>x</em>² = 2

<em>x</em>² = 8/2 = 4

<em>x</em> = ± √4 = ± 2

You can then use the second derivative to determine the concavity of <em>P</em>, and its sign at a given critical point decides whether it is a minimum or a maximum.

We have

d²<em>P</em>/d<em>x</em>² = 16/<em>x</em>³

When <em>x</em> = -2, the second derivative is negative, which means there's a relative maximum here.

When <em>x</em> = 2, the second derivative is positive, which means there's a relative minimum here.

So, <em>P</em> has a relative maximum value of 8/(-2) + 2(-2) = -8 when <em>x</em> = -2.

7 0
3 years ago
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