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Galina-37 [17]
3 years ago
5

Which term refers to the process by which land is worn away by natural forces or human activity

Chemistry
2 answers:
Phoenix [80]3 years ago
8 0

Answer:

A- erosion

Explanation:

Erosion occurs when water, wind, or ice removes soil and rock and deposits it in a new area.

Occurs naturally, but is also impacted by human activity.

Caused by farming, deforestation, and building roads and cities.

Juliette [100K]3 years ago
5 0

Answer:

The answer is A. Erosion

Explanation:

Took the quiz

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What characterizes a homogeneous mixture?
Vadim26 [7]
It has the same composition throughout, unlike a heterogeneous which has visibly separate substances
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3 years ago
Uestion 3 (1 point)
elena-s [515]

Answer:

density=mass/volume.

density=14/18

=0.777777777 ~ 0.8g/ml.

It will float because the it lesser than the density of water.

6 0
3 years ago
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How do lawmakers make good environmental decisions??
Sliva [168]
<h2>Answer : By weighing the costs and benefits of an environmental issue </h2><h3> Explanation :</h3>

The law makers usually conduct many studies before a law is imposed. They try to explore many other options available to the current environmental issue and then come to a conclusion to make a law.

They also weigh the cost aspect along with the benefit of the ongoing environmental issue. They try to come up with something which appears to be cost effective and result bearing.

4 0
3 years ago
Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

3 0
3 years ago
Write the formula for the conjugate base for the following acids. <br>Thank you ​
Llana [10]

Answer:

See the answer and explanation below , please.

Explanation:

A conjugate base is defined as that formed after an acid donates its proton.

For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:

a) HF + H20 --> F- + H30+      

b) H20+ H20 --> OH-  + H30+

C)H2PO3-  + H20--> HPO3 2-   + H30+

d) HSO4- + H20 -->  SO4 2- + H30+

E) HCL02 + H20 --> CLO02 -   + H30+

7 0
3 years ago
Read 2 more answers
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