Question

If gas in a sealed container has a pressure of 50 kpa at 300 k, what will the pressure be if the temperature rises to 360 k? 161 kpa 16 kpa 60 kpa 41 kpa

Answer 1

$60 \; \text{kPa}$

The pressure an ideal gas exerts on a sealed container of fixed volume is directly related to its temperature in degrees Kelvin. That is:

$T_1 / T_2 = P_1 / P_2$

In this scenario:

• $T_1 = 300 \; \text{K}$
• $P_1 = 50 \; \text{kPa}$
• $T_2 = 360 \; \text{K}$

Rearranging gives

$\begin{array}{lll}P_2 &=& P_1 \cdot T_2 / T_1 \\ &=& 50 \; \text{kPa} \times (360 \; \text{K})/ (300 \; \text{K})\\ &=& 60 \; \text{kPa}\end{array}$