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3 years ago

5

Reactions rates for reactions occurring in solution can be increased by increasing the concentration of the solution. With gases

you can do something similar, which is to -

1 answer:

LUCKY_DIMON [66]3 years ago

4 0

"Increase Pressure " is the right answer. if you need help , let me know

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A chemist must dilute 34.3mL of 1.72mM aqueous calcium sulfate solution until the concentration falls to 1.00mM. He'll do this b

EastWind [94]

Answer:

58.9mL

Explanation:

Given parameters:

Initial volume = 34.3mL = 0.0343dm³

Initial concentration = 1.72mM = 1.72 x 10⁻³moldm⁻³

Final concentration = 1.00mM = 1 x 10⁻³ moldm⁻³

Unknown:

Final volume =?

Solution:

Often times, the concentration of a standard solution may have to be diluted to a lower one by adding distilled water. To find the find the final volume, we must recognize that the number of moles of the substance in initial and final solutions are the same.

Therefore;

C₁V₁ = C₂V₂

where C and V are concentration and 1 and 2 are initial and final states.

now input the variables;

1.72 x 10⁻³ x 0.0343 = 1 x 10⁻³ x V₂

V₂ = 0.0589dm³ = 58.9mL

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3 years ago

The is the rate which a substance undergoes a chemical change

choli [55]

Reaction Rate is the rate at which a substance undergoes a chemical change.

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3 years ago

When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H

algol [13]

Answer: The empirical formula is $CH_2$ and molecular formula is $C_4H_8$

Explanation:

We are given:

Mass of $CO_2$ = 18.95 g

Mass of $H_2O$ = 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, = $\frac{12}{44}\times 18.59=5.07g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, = $\frac{2}{18}\times 7.759=0.862g$ of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.422}{0.422}=1$

For H = $\frac{0.862}{0.422}=2$

The ratio of C : H = 1: 2

Hence the empirical formula is $CH_2$ .

The empirical weight of $CH_2$ = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4$

The molecular formula will be= $4\times CH_2=C_4H_8$

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2 years ago

What is the most important part of driving

Romashka-Z-Leto [24]

I think learn to drive is the most important part

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3 years ago

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Doubling the amplitude of a wave means that you increase the ___ of a wave factor of _______

Nesterboy [21]

Doubling the amplitude of a wave means that you increase the energy of a wave factor of quadrupling

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3 years ago