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stiks02 [169]
2 years ago
12

Find the value c that will make 9x^2 +30x+c a perfect square trinomial

Mathematics
2 answers:
anzhelika [568]2 years ago
8 0

Answer:

c = 25

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u>

  • A quadratic equation is given to us.
  • The equation is 9x² + 30x + c .

And we need to find out the value of c for which the given trinomial is a perfect square. On looking at the given expression all the terms are having positive signs before them .So we can rewrite it on the basis of ,

<u>Identity</u><u> </u><u>:</u><u>-</u><u> </u>

\implies (a+b)^2=a^2+b^2+2ab

Let's try to set the equation on this Identity .

The firsr term is 9x² . We can write it as ,

\implies 9x^2=(3x)^2

Hence the middle term here should contain 3 and 2 as their factors. Let's Break the middle term .

\implies 30x = 2.3x.5

Therefore in order to make the whole expression as perfect square 5² must be replaced by c . The expression would become ,

\implies 9x^2+30x + 5^2 \\\\\implies (3x)^2+2.3x.5 +5^2\\\\\implies (3x+5)^2

<u>Hence </u><u>the </u><u>value </u><u>of </u><u>c </u><u>should</u><u> be</u><u> </u><u>2</u><u>5</u><u> </u><u>.</u>

Anika [276]2 years ago
5 0
C = 25 you just multiply step by step exactly how it shows it on the problem/how u wrote it
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The answer would be a total of 9 blue stripes.
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3 years ago
What is negative five over eight -5/8 b = 10
anastassius [24]
- \frac{5}{8}\cdot b = 10 \ \ \ |multiply\ both\ sides\ by\ (-\frac{8}{5}) \\\\(-\frac{8}{5})\cdot (- \frac{5}{8})\cdot b =(-\frac{8}{5})\cdot 10\\\\b=(-8)\cdot 2\\\\b=-16


8 0
3 years ago
Mr. Dunford will give 6 pencils to each of his 30 students in his class. There are 12 pencils in each box he will order. He has
horsena [70]

Answer:

The answer to this problem is 4

Step-by-step explanation:

6 0
3 years ago
Consider the following system of equations. -10x2-10y2=-300 5x2+5y2=150 Which statement describes why the system has infinite so
scoundrel [369]

Answer:

The equations represent circles that result in the same graph.

Step-by-step explanation:

we have

-10x^{2}-10y^{2}=-300

Divide by -10 both sides

x^{2}+y^{2}=30 -----> equation A

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

and

5x^{2}+5y^{2}=150

Divide by 5 both sides

x^{2}+y^{2}=30 -----> equation B

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

equation A and equation B are equal

therefore

The system has infinite solutions, because the equations represent circles that result in the same graph.

4 0
3 years ago
mauricio estimates that the first module of the project could be completed in as few as 15 days or could take as many as 25 days
4vir4ik [10]

Answer:

<em>Most likely time, </em>according to PERT (Program evaluation and review technique).

Step-by-step explanation:

PERT is "a statistical tool used in <em>project management" (Program evaluation and review technique (2020), </em>in Wikipedia), and it is commonly used with CPM <em>(Critical Path Method)</em> to manage projects.

Inside PERT, there are different defined times to accomplished an activity in a project, that is:

  • An <em>optimistic time</em> or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
  • A <em>pessimistic time, </em>a time quite the opposite to optimistic time.
  • A <em>most likely time</em>, or a time required to accomplished an activity if everything goes as expected or normally.
  • An <em>expected time</em>, an statistical estimation.

Considering the question, we have that the <em>time</em> when "the first module of the project could be completed":

  • "[...] in as few as 15 days"  is the <em>optimistic time</em>.
  • "[...] or could take as many as 25 days" is the <em>pessimistic time</em>.
  • "[...] but most likely will require 20 days" is the <em>most likely time</em>.

As a result, the <em>20-day estimate</em> is called the <em>most likely time</em> in the context of the PERT/CPM techniques.

3 0
3 years ago
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