<span>E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2
E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64
V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1</span>
to solve for y, we must multiply by t on both side to get ride of the t in the denominator. By doing this, we will get:
on the right side.
Subtracting 3, and we have successfully isolated y.
It would be impossible to get a quantitative value for y if we don't know the value of t.
you have it right 5 is 1 you just divide it by 10 again but for #7 and 10 its 8 over 10 and 6 over 10 cause its not in the 10s yet hope i helped
Answer:
a c e
Step-by-step explanation:
Brainliest Please?
