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Ostrovityanka [42]
3 years ago
6

I need help with this ​

Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer:

correct

Step-by-step explanation:

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Applications of integers (PLEASE HELP)
Amiraneli [1.4K]

Answer:

I can try to answer.

Step-by-step explanation:

1. 23

2. 25

3. week 4 is 29, and week 3 is 23

29-23=6

4. week 5 and 7 because on week 4 it was 29, it dropped to 25 on week 5. On week 6 it was 37, then dropped to 34 on week 7.

Im not rlly sure about 5, but ill answer it if I figure it out.

5 0
2 years ago
Which function do you evaluate first in g(f(x))? f(x) g(x) f(g(x))
Mazyrski [523]

For the composite function g(f(x)), the function f(x) goes first in terms of evaluation. This is the inner most function. You would read it from right to left in terms of determining the order of evaluation.

4 0
3 years ago
Read 2 more answers
What is the difference in minutes of median
REY [17]

<h2>Answer:</h2>

The answer is 25 minutes

<h2>Step-by-step explanation:</h2>

As we see the median time given in minutes before the installation was 53 minutes and after the installation it became 28 so by taking the difference which is 53 - 28 gives us 25 minutes.

8 0
3 years ago
What is the rate of change: y=x+5
const2013 [10]

Answer:

x or 1x.

Step-by-step explanation:

The rate of change is slope.

Slope=m

y=mx+b

y=<u>x</u>+5

x is the same thing as 1x. So...

4 0
2 years ago
Define fn : [0,1] --&gt; R by the
sasho [114]

Answer:

The sequence of functions \{x^{n}\}_{n\in \mathbb{N}} converges to the function

f(x)=\begin{cases}0&0\leq x.

Step-by-step explanation:

The limit \lim_{n\to \infty }c^{n} exists and converges to zero whenever \lvert c \rvert. But, if c=1 the sequence \{c^{n}\} is constant and all its terms are equal to 1, then converges to 1. Using this result, consider the sequence of functions \{f_{n}\} defined on the interval [0,1] by f_{n}(x)=x^{n}. Then, for all 0\leq x we have that \lim_{n\to \infty}x^{n}=0. Now, if x=1, then \lim_{n\to \infty }x^{n}=1. Therefore, the limit function of the sequence of functions is

f(x)=\begin{cases}0&0\leq x.

To show that the convergence is not uniform consider 0. For any n>1 choose x\in (0,1)  such that \varepsilon^{1/n}. Then

\varepsilon

This implies that the convergence is not uniform.

8 0
3 years ago
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