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3 years ago

10

You are trying to figure out how many license plates can be created from the digits 0 through 9. The license plate has 6 numbers

, and none can be repeated. How many license plates can be created?

1 answer:

Vladimir [108]3 years ago

7 0

Answer:

1

Step-by-step explanation:

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Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

$P(X$

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

$P(X$

Take natural log on both sides.

$ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30$

Thus, the value of x is 30.

7 0

3 years ago

Twelve friends came to Guy’s birthday party. He received seven gifts and a total of $95 in cash for his birthday. He buys an air

V125BC [204]

$95-$9 = $86 / $8 = 10 animal shelters with a remainder of $6

I hope this helps! :)

4 0

3 years ago

Read 2 more answers

You are going to have a birthday party and serve pizza. You plan to order pepperoni pizza

Ronch [10]

Answer:

70 pepperoni 30 sausage

Step-by-step explanation:

30 times 6 is 180

70 times 8 is 560

180 plus 560 is 740

5 0

2 years ago

Anna [14]

For a cone, the equation for volume would be
V = π r^2 h/3.

( volume = pi x radius squared x height / 3)

To find the volume for this question, you would set up the equation like this:

V = π x 2^2 x 12 / 3

Then, following the order of operation, you would do the following:

V = π x 4 x 12 / 3

(You get the 4 from 2 squared)

V = π x 4 x 4

(You get the second 4 from dividing 12 by 3)

V = π x 16

(You get 16 from multiplying 4 and 4)

V = 16π

(You get 16π from multiplying 16 and π, and the number is always in front of the π, so you would never get a π16, it would only be 16π)

So, your volume would be 16π, which is answer D.

I hope I helped! c:

7 0

3 years ago

In a game a player draws and replaces a card from a deck 2 times. The possible outcomes and payouts are shown. What is the

Goshia [24]

<u>Given</u>:

Given that in a game a player draws and replaces a card from a deck 2 times.

The possible outcomes and payouts are given.

We need to determine the expected value for someone playing the game.

<u>Expected value:</u>

The expected value for someone playing the game can be determined by

$EV=(\frac{26}{52})(\$ 20)+(\frac{52}{52})(\$4)+(\frac{52}{52})(\$ 0)+(\frac{26}{52})(-\$12)$

Simplifying the values, we have;

$EV=(\frac{1}{2})(\$ 20)+(1)(\$4)+(1)(\$ 0)+(\frac{1}{2})(-\$12)$

Dividing the terms, we get;

$EV=\$ 10+\$4+\$ 0+-\$6$

Adding, we have;

$EV=\$ 8$

Thus, the expected value for someone playing the game is $8

3 0

3 years ago