Answer:
sentence = "hello wow a stores good"
same_letter_count = 0
sentence_list = sentence.split()
for s in sentence_list:
if s[0] == s[-1]:
same_letter_count += 1
print(same_letter_count)
Explanation:
*The code is in Python.
Initialize the sentence with a string
Initialize the same_letter_count as 0
Split the sentence using split method and set it to the sentence_list
Create a for loop that iterates through the sentence_list. If the first and last of the letters of a string are same, increment the same_letter_count by 1
When the loop is done, print the same_letter_count
Answer:
make sure the speaker is clean and you volume setting is on normal there is alot of setting for deaf people so make sure that is correctly
Providing audio with images
Answer:
Short-circuit evaluation is performed with the not operator.
Answer:
Part a: The program will print 3.
Part b: The program will print 4
Part c: The program will print 1.
Explanation:
Part a: As the scoping is static, the x integer has a value of 1 and the y integer has a value of 2 so the addition is 2+1=3.
Part b: As the scoping is dynamic with deep binding, the x integer has a value of 2 and the y integer has a value of 2 so the addition is 2+2=4.
Part c: As the scoping is dynamic with shallow binding, the x integer has a value of 1 so it will print 1.
