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maxonik [38]
3 years ago
7

How do I determine if a function is even, odd, or neither​

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0

Answer:

The way to do is dow below

Step-by-step explanation:

You may be asked to "determine algebraically" whether a function is even or odd. To do this, you take the function and plug –x in for x, and then simplify. If you end up with the exact same function that you started with (that is, if f (–x) = f (x), so all of the signs are the same), then the function is even.

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maria [59]

Answer:

14/33

Step-by-step explanation:

The total amount of beads is 8+4 = 12.  8 of these are black beads, so that is what we want, so 8/12 or 2/3.  For the second one, one black bead is already taken so 8-1 = 7 are left and for the total 12 - 1 = 11 are left, so 7/11.  Multiply this by 2/3 and we get 14/33.

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Answer:

4 Tables

Step-by-step explanation:

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4 0
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Read 2 more answers
Please I need help with this!!!!!!!
inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

   x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}

   x=\sqrt[3]{5^4} [Since, a^{\frac{1}{3}}=\sqrt[3]{a}]

   x=\sqrt[3]{5\times 5\times 5\times 5}

   Step 5:

   x=\sqrt[3]{(5)^3\times 5}

   x=\sqrt[3]{5^3}\times \sqrt[3]{5}

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

   (3x-1)^{\frac{1}{5}}=2

   Step 1:

   (3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}

   Step 2:

   (3x-1)=2^5

   Step 3:

   3x=32+1

   Step 4:

   x=11

4). By substituting x=11 in the original equation.

   (3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}

                         =(2^5)^\frac{1}{5}

                         =2

There is no extraneous solution.

3 0
3 years ago
The is a function of the
Delvig [45]

Answer:

Is this the right question?

Step-by-step explanation:

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Answer:

4 to 7 *maybe

Step-by-step explanation:

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