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aivan3 [116]
3 years ago
5

Help please I dont know what to do

Mathematics
2 answers:
KIM [24]3 years ago
7 0
Hope this helps:) the fracción is the 1/2 part

ser-zykov [4K]3 years ago
3 0

Answer:

7 1/2 = 1/2

15 = 1

22 1/2 = 1 1/2

30= 2

37 1/2= 2 1/2

Explanation: add 7 1/2 twice which equals 15 for 1 30 for two but have of 15 is 7 1/2 so add 15 and 7 1/2 to the other 2.

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CAN SOMEONE HELP?<br><br>Find the value of x?​
Anna007 [38]

Answer:

x = 1

Step-by-step explanation:

Δ ABC and Δ DEF are congruent ( SAS postulate )

Thus corresponding sides are congruent that is

BC = EF , substitute values

13x - 12 = 7x - 6 ( subtract 7x from both sides )

6x - 12 = - 6 ( add 12 to both sides )

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3 0
3 years ago
Will these three sides form a right triangle 7yd,3yd,9yd ? yes or no?
Brut [27]

Answer:

No, these three sides form a right triangle 7yd,3yd,9yd wont work

Step-by-step explanation:

a^2 + b^2 = c^2

lonest length is c (hypotenuse) : 9yd

(7)^2 + (3)^2 = (9)^2

49 + 9 = 81

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3 0
2 years ago
The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 13.1 years; the
Marat540 [252]

Answer:

P(x

We can calculate the z score given by:

z =\frac{x-\mu}{\sigma}= \frac{14.6-13.1}{1.5}= 1

So for this case 14.6 is a value 1 deviation above the mean

We know that within 1 deviation from the mean we have 68% of the data, and on the tails we will have 100-68 = 32% and 16% on each tail, so then we can conclude that:

P(X

Step-by-step explanation:

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

Let X the random variable who represent the lifespans of meerkats.

From the problem we have the mean and the standard deviation for the random variable X. E(X)=13.1, Sd(X)=1.5

So we can assume \mu=13.1 , \sigma=1.5

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

And we want the following probability:

P(x

We can calculate the z score given by:

z =\frac{x-\mu}{\sigma}= \frac{14.6-13.1}{1.5}= 1

So for this case 14.6 is a value 1 deviation above the mean

We know that within 1 deviation from the mean we have 68% of the data, and on the tails we will have 100-68 = 32% and 16% on each tail, so then we can conclude that:

P(X

3 0
3 years ago
Read 2 more answers
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Aleksandr-060686 [28]

Answer:

13

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i did the assignment

5 0
4 years ago
Could somebody please help me
Bas_tet [7]
Yes what do u need help with ?
4 0
3 years ago
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