Find the area and perimeter of a rectangle. the length is x+6 the width is x+2

Mathematics

1 answer:

yarga [219]2 years ago

6 0

Answer:

<h2><u><em>Area = x² + 8x + 12</em></u></h2><h2><u><em>Perimeter = 4x + 16</em></u></h2>

Step-by-step explanation:

The area of a rectangle is given by the formula:

Area=width×height

The perimeter of a rectangle is given by the formula

Perimeter=2(width+height)

Area

(x + 6) × (x+2) =

x² + 2x + 6x + 12

x² + 8x + 12

------------------

Perimeter

2 × (x + 6 + x + 2) =

2 × (2x + 8) =

4x + 16

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Choose the correct description of the graph of the inequality x - 3 >= 5.

lions [1.4K]

The <em><u>correct answer</u></em> is:

D) Closed circle on 8, shading to the right.

Explanation:

First we must solve the inequality:

x - 3 ≥ 5

Add 3 to each side:

x - 3 + 3 ≥ 5 + 3

x ≥ 8

To graph this, we want a circle on 8 Since it is "greater than or equal to," 8 is included in the solution set. This means the circle will be closed.

Since it is "greater than," we want the numbers to the right of 8 on the number line.

This means the inequality will be a closed circle and shaded to the right.

8 0

3 years ago

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Solve the equation 3/4x+3-2x = -1/4+1/2x+5

elena55 [62]

Hi there! The answer is x = -1

Let's solve this equation step by step!
$\frac{3}{4} x + 3 - 2x = - \frac{1}{4} + \frac{1}{2} x + 5$

First collect terms.
$- 1 \frac{1}{4} x + 3 = \frac{1}{2} x + 4 \frac{3}{4}$

Subtract (1/2)x from both sides.
$- 1\frac{3}{4} x + 3 = 4 \frac{3}{4}$

Subtract 3 from both sides.
$- 1\frac{3}{4} x = 1 \frac{3}{4}$

And finally divide by -1 3/4
$x = \frac{7}{4} \div - \frac{7}{4} = \frac{7}{4} \times - \frac{4}{7} = - \frac{28}{28} = - 1$