First, take 75 and divide it by 100. (0.75)
Then, take your answer, 0.75, and multiply it by 42.
0.75 x 42 = 31.5
Your answer is 31.5, or answer 3.
Answer:
4 feet
Step-by-step explanation:
see the attached figure with letter to better understand the problem
we know that
A board is half way up each ladder
so
point B is the midpoint segment AC and point F is the midpoint segment AG
Than means
AB=AC/2 -----> AB=10/2=5 units
BF is parallel to segment CG ----> by Triangle midpoint segment theorem
step 1
In the right triangle ABD
Find the length side AD
Applying Pythagorean Theorem
solve for AD
step 2
Find the length of segment DE (h)
Remember that
If two triangles are similar, then the ratio of its corresponding sides is proportional
In this problem
Triangles ABD and ACE are similar by AA Similarity Theorem
so
substitute the given values
----> by segment addition postulate
substitute
solve for DE
therefore
The distance from the bucket to the ground is 4 feet
*see attachment for diagram
Answer:
C.KM = 15
D.KL = 17
F.Perimeter or triangle JKL = 50
Step-by-step explanation:
Given:
JL = 16,
KM = 4x-1
JK = 6x - 7
KL = 5x - 3
✔️Thus, let's find the value of x
Since KM is a perpendicular bisector of JL, it means JM = LM = ½*16 = 8
KM in ∆KJM is equal to KM in ∆KLM.
The angles opposite the two corresponding congruent sides in both triangles are also congruent to each other. Therefore, the third corresponding side and angles would be congruent to each other.
Thus:
JK = KL
6x - 7 = 5x - 3 (substitution)
Collect like terms
6x - 5x = 7 - 3
x = 4
✔️Find JK:
JK = 6x - 7
Plug in the value of x
JK = 6(4) - 7
JK = 24 - 7
JK = 17
✔️Find KM:
KM = 4x - 1
Plug in the value of x
KM = 4(4) - 1
KM = 16 - 1
KM = 15
✔️Find KL:
KL = 5x - 3
Plug in the value of x
KL = 5(4) - 3
KL = 20 - 3
KL = 17
✔️Find the Perimeter of ∆KLM:
Perimeter of ∆KLM = KM + KL + LM
= 15 + 17 + 8
= 40
✔️Find the Perimeter of JKL:
Perimeter of ∆JKL = JK + KL + JL
= 17 + 17 + 16
= 50.
The correct values are:
C.KM = 15
D.KL = 17
F.Perimeter or triangle JKL = 50
Easiest way is algebra so
x+y are 2 numbers
if (x+y)/2=44
and x or y=12 (pic one)
so if x=12
subsitute
(12+y)/2=44
multiply both sdies by 2 to clear fraction
12+y=88
subtract 12 from both sides
y=76
the numbers are 12 and 76