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Kamila [148]
2 years ago
14

Abosolute value of -5

Mathematics
1 answer:
professor190 [17]2 years ago
3 0
The absolute value of -5: 5
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The volume of a cylinder is 375 pi m^3. if r= 5 m, find its height.
pishuonlain [190]

Answer:

Step-by-step explanation:

V=h\pi r^2\\ \\ h=\frac{V}{\pi r^2}\\ \\ h={375\pi}{25\pi}\\ \\ h=15m

3 0
3 years ago
NEED ANSWER ASAP!!! Express your answer in scientific notation. 9.3 X 107 - 3.14 X 106
kirza4 [7]

Answer:

89.86\times 10^6

Step-by-step explanation:

9.3\times 10^7 - 3.14\times 10^6\\

In order to simplify the above expressions we make sure that we get same powers of 10 for both the terms.

So, we multiply and divide the first term with 10

Dividing first term by 10.

\frac{9.3\times 10^7}{10}\\9.3\times 10^{7-1}\\9.3\times 10^6\\

Now multiplying it by 10.

10\times9.3\times 10^6\\93\times 10^6

Evaluating the new expressions.

93\times 10^6 - 3.14\times 10^6\\

Taking 10^6 common factor out.

(93-3.14)\ties 10^6

=89.86\times 10^6

5 0
3 years ago
What is the interquartile range of the data set? {48, 50, 65, 60, 80, 42, 45, 50, 42, 55, 45}
MissTica
Order the number:
42,42,45,45,48,50,50,55,60,65,80

Mean:50
Quartile 1:45
Quartile 3:60

60-45=15. As a result, the interquartile range is 15. Hope it help!
5 0
3 years ago
Read 2 more answers
Which expression is equivalent to 2(3g - 4) - (8g + 3)?
kolbaska11 [484]

Answer:

Step-by-step explanation:

6 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
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