The following compounds and the number and type of ions are as follows:
Gold and chloride:
Gold (III) = Au 3+
Chloride = Cl 1-
Calcium and Sulfate:
Calcium Sulfate:
Calcium = Ca 2+
Sulfate = SO4 2-
Magnesium and Hydroxide
Magnesium Hydroxide: Mg(OH)2
Magnesium: Mg 2+
Hydroxide: (OH) 1-
Answer:
N=100×10÷49= 20.41 near Answer is point C
Answer:
Equilibrium concentration of 
is 12.5 M
Explanation:
Given reaction: 
Here, ![K_{c}=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}][H_{2}O]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BC_%7B2%7DH_%7B5%7DOH%5D%7D%7B%5BC_%7B2%7DH_%7B4%7D%5D%5BH_%7B2%7DO%5D%7D)
where 
represents equilibrium constant in terms of concentration and species inside third bracket represent equilibrium concentrations
Here, ![[C_{2}H_{4}]=0.015M](https://tex.z-dn.net/?f=%5BC_%7B2%7DH_%7B4%7D%5D%3D0.015M)
, ![[C_{2}H_{5}OH]=1.69M](https://tex.z-dn.net/?f=%5BC_%7B2%7DH_%7B5%7DOH%5D%3D1.69M)
and 
So, ![[H_{2}O]=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}]\times K_{c}}=\frac{1.69}{0.015\times 9.0}=12.5M](https://tex.z-dn.net/?f=%5BH_%7B2%7DO%5D%3D%5Cfrac%7B%5BC_%7B2%7DH_%7B5%7DOH%5D%7D%7B%5BC_%7B2%7DH_%7B4%7D%5D%5Ctimes%20K_%7Bc%7D%7D%3D%5Cfrac%7B1.69%7D%7B0.015%5Ctimes%209.0%7D%3D12.5M)
Hence equilibrium concentration of is 12.5 M
Atp is a form of energy and it is generated through a chemical process called substrate level phosphorylation.
<h3 /><h3>What is substrate level phosphorylation?</h3>
Substrate-level phosphorylation is a reaction that makes use of substrate to generate Adenosine triphosphate (ATP) which is a form of energy.
ATP is produced through the transfer of phosphate group from the substrate directly to adenosine diphosphate (ADP).
Therefore, substrate-level phosphorylation generates the atp produced in glycolysis.
Learn more on substrate level phosphorylation here,
brainly.com/question/7331523
