Answer:
7800 cells
Explanation:
The number of Escherichia coli cells N after n generations is given by
N = 2ⁿ × N₀ where N₀ = initial population
Now making N₀ subject of the formula, we have
N₀ = N/2ⁿ
Since n = 8 and N = 1,996,800 cells, substituting the values of the variables into the equation, we have
N₀ = N/2ⁿ
N₀ = 1,996,800 cells/2⁸
N₀ = 1,996,800 cells/256
N₀ = 7800 cells
So, the initial population of Escherichia coli cells is 7800 cells.
Answer:
The mass of the atom will change
Explanation:
The mass of the atom will alter if the changing the amount of electrons in an atom charge would result in being positively or negatively charged (Correct me if I'm incorrect sorry If I got this wrong)
<span>A 18 M solution of an acid that ionizes only slightly in solution would be termed
concentrated and weak. The concentration of the acid is high. The acid which dissociates partially in water is a weak acid.
</span><span>Calculate the [H^+] for the aqueous solution in which [OH^-] is 1 x10^-9. Is this solution acidic, basic or neutral. To determine [H+] use:
1x10^-14 = [OH-][H+]
solve for [H+]
[H+] = 1x10^-14/1x10^-9
= 1x10^-5</span>
Answer:
For 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).
Explanation:
<u>Step 1: </u>Data given
Number of moles of Pb(ClO2)2 = 1
Since the oxidation number of Pb is 2+ and the oxidation number of ClO2 is -1
So to bind we should have <u>twice</u> ClO2
1 mole of Pb(ClO2)2 contains 1 mole of Pb; 1*<u>2</u>= 2 moles of Cl and 2*<u>2</u> = 4 moles of 0.
This means for 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).
Answer:
1.225g
Explanation:
From the question given,
Volume of diamond = 0.35cm^3
Density of diamond = 3.5g/cm^3
Mass of diamond =?
Density = Mass /volume
Mass = Density x volume
Mass = 3.5 x 0.35
Mass of diamond = 1.225g
