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Nata [24]
3 years ago
15

Which chemical process generates the atp produced in glycolysis?.

Chemistry
1 answer:
Naddik [55]3 years ago
8 0

Atp is a form of energy and it is generated through a chemical process called substrate level phosphorylation.

<h3 /><h3>What is substrate level phosphorylation?</h3>

Substrate-level phosphorylation is a reaction that makes use of substrate to generate Adenosine triphosphate (ATP) which is a form of energy.

ATP is produced through the transfer of phosphate group from the substrate directly to adenosine diphosphate (ADP).

Therefore, substrate-level phosphorylation generates the atp produced in glycolysis.

Learn more on substrate level phosphorylation here,

brainly.com/question/7331523

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The mixture gave off heat

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10. (a) Describe how the structure of an alloy is different to a pure metal
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5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
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Help
4 0
3 years ago
what is the percent by mass concentration of a solution that contains 5.30 grams of salt dissolved in 19.7 g of water​
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0.212

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(5.30g) / (5.30g + 19.7g)

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How many grams of O2 are in 5.0 moles of the oxygen gas?
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At 85°C, the vapor pressure of A is 566 torr and that of B is 250 torr. Calculate the composition of a mixture of A and B that b
Phantasy [73]

Answer:

Composition of the mixture:

x_{A} =0.652=65.2 %

x_{B} =0.348=34.8 %

Composition of the vapor mixture:

y_{A} =0.809=80.9%

y_{B} =0.191=19.1%

Explanation:

If the ideal solution model is assumed, and the vapor phase is modeled as an ideal gas, the vapor pressure of a binary mixture with x_{A} and x_{B} molar fractions can be calculated as:

P_{vap}=x_{A}P_{A}+x_{B}P_{B}

Where P_{A} and P_{B} are the vapor pressures of the pure compounds. A substance boils when its vapor pressure is equal to the pressure under it is; so it boils when P_{vap}=P. When the pressure is 0.60 atm, the vapor pressure has to be the same if the mixture is boiling, so:

0.60*760=P_{vap}=x_{A}P_{A}+x_{B}P_{B}\\456=x_{A}P_{A}+(1-x_{A})P_{B}\\456=x_{A}*(P_{A}-P_{B})+P_{B}\\\frac{456-P_{B}}{P_{A}-P_{B}}=x_{A}\\\\\frac{456-250}{566-250}=x_{A}=0.652

With the same assumptions, the vapor mixture may obey to the equation:

x_{A}P_{A}=y_{A}P, where P is the total pressure and y is the fraction in the vapor phase, so:

y_{A} =\frac{x_{A}P_{A}}{P}=\frac{0.652*566}{456} =0.809=80.9 %

The fractions of B can be calculated according to the fact that the sum of the molar fractions is equal to 1.

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3 years ago
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