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2 years ago

Which chemical process generates the atp produced in glycolysis?.

1 answer:

8 0

Atp is a form of energy and it is generated through a chemical process called substrate level phosphorylation.

<h3 /><h3>What is substrate level phosphorylation?</h3>

Substrate-level phosphorylation is a reaction that makes use of substrate to generate Adenosine triphosphate (ATP) which is a form of energy.

ATP is produced through the transfer of phosphate group from the substrate directly to adenosine diphosphate (ADP).

Therefore, substrate-level phosphorylation generates the atp produced in glycolysis.

Learn more on substrate level phosphorylation here,

brainly.com/question/7331523

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What causes salinization

Svet_ta [14]

Answer:

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Explanation:

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3 years ago

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Answer:

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Explanation:

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2 years ago

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if you drink the water your not 1year old you can drink just little.

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2 years ago

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A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther

sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

$T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )$

1. Calculate the thermometer readings after 0.5 min and 1 min

(a) After 0.5 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}$

(b) After 1 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}$

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

t = t - 1, because the cooling starts 1 min late

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}$

3. Plot the temperature readings as a function of time.

The graphs are shown below.

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2 years ago

Predict whether each of the following molecules is polar or nonpolar? 1. XeF4 3. CCl4 5. CH3Br

denpristay [2]

The answer the following are as follows:

<span> 1. XeF4 - molecules are polar

3. CCl4 - molecules are polar

5. CH3Br - molecules are non-polar

I hope my answer has come to your help. God bless and have a nice day ahead!</span>

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3 years ago