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2 years ago

Which chemical process generates the atp produced in glycolysis?.

1 answer:

8 0

Atp is a form of energy and it is generated through a chemical process called substrate level phosphorylation.

<h3 /><h3>What is substrate level phosphorylation?</h3>

Substrate-level phosphorylation is a reaction that makes use of substrate to generate Adenosine triphosphate (ATP) which is a form of energy.

ATP is produced through the transfer of phosphate group from the substrate directly to adenosine diphosphate (ADP).

Therefore, substrate-level phosphorylation generates the atp produced in glycolysis.

Learn more on substrate level phosphorylation here,

brainly.com/question/7331523

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Why can't all mixtures be classified as solutions?

shusha [124]

D. Not all mixtures are heterogeneous

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2 years ago

HI(aq)+NaOH(aq)→ <br> what the final balanced chemical equation with the phases included

julia-pushkina [17]

Answer:

$HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)$

Explanation:

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In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

$HI(aq)+NaOH(aq)\rightarrow NaI+H_2O$

Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

$HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)$

Which is also balanced as the number of atoms of all the elements is the same at both sides.

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2 years ago

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Answer:

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Explanation:

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2 years ago

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Which is the net result of the proton-proton chain? 6 protons = 2 heliums + 3 positrons + 3 neutrinos + gamma rays 4 protons = 1

saveliy_v [14]

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2 years ago

In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,

Vika [28.1K]

Answer:

The answer is: 11759 Hz

Explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

$\delta (ppm) = \frac{Observed\,frequency (Hz)}{Frequency\,\, of\,\,the\,Spectrometer (MHz)} \times 10^{6}$

$\therefore Observed\,frequency (Hz)= \frac{\delta (ppm)\times Frequency\,\, of\,\,the\,Spectrometer (MHz)}{10^{6}}$

$Observed\,frequency= \frac{211.5 ppm \times 556 \times 10^{6} Hz}{10^{6}} = 11759 Hz$

<u>Therefore, the signal is at 11759 Hz from the TMS.</u>

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3 years ago