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Mandarinka [93]
4 years ago
15

Normality (N) of concentratedH2SO4 isa. 12b. 36c. 24d. 48​

Chemistry
1 answer:
kolezko [41]4 years ago
6 0

Answer:

N=100×10÷49= 20.41 near Answer is point C

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Ultrasound is used to break up kidney stones. How do sound waves break up kidney stones?
dolphi86 [110]

Answer:

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Explanation:

hope this helps

4 0
3 years ago
What is the hydrogen ion concentration of 0.450M solution of acetic acid (HC2H3O2), if the ionization constant(Ka) is 2.19 x 10-
WITCHER [35]

Answer:

3.02 Mm

Explanation:

3 0
3 years ago
How many miles of C atoms are present in a sample of 3.85x1024 C atoms?
alekssr [168]
Answer:
number of moles = 6.393 moles

Explanation:
One mole of any substance contains Avogadro's number (6.022 * 10^23) of atoms. 
Therefore, to know the number of moles that contain 3.85 * 10^24 atoms, all we have to do is cross multiplication as follows:
1 mole ......................> 6.022 * 10^23
?? moles ..................> 3.85 * 10^24
number of moles = (3.85 * 10^24 *1) / (6.022 * 10^23)
number of moles = 6.393 moles

Hope this helps :)
8 0
3 years ago
Which best illustrates the way in which radiation? Giving brainy.
Ilya [14]

Answer:

I dont really understand your question. but maybe this might help.

https://quizlet.com/283377931/radiation-flash-cards/

Explanation:

4 0
3 years ago
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
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