We’re getting married bro

Tyler baked 702 cookies. He sold them in boxes of 18. After selling all of the boxes of cookies for the

user100 [1]

Answer:

3.50

Step-by-step explanation:

if you divide 18 by 702 you will get 39 and 136.50 divided by 39 is 3.50. and to make sure this is right you can multiply 3.50 by 39 and you will get 136.50

3 0

3 years ago

Read 2 more answers

Helppppppppppppppppmeeeeeeeeeeeeeeeeeeee

KonstantinChe [14]

Answer:

hope this answer helps you dear...take care!

5 0

2 years ago

The two perpendicular lines of a coordinate plane that intersect at the origin (singular: axis)

Svetach [21]

3. Axes
That’s what it should be

3 0

2 years ago

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10. Jan purchased 140 shares of stock in the ABC Company at a price of $18.75 per share. During the

andre [41]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given :- }}$

Jan purchased 140 shares of stock in ABC company at a price of $18.75 per share
During the next 3 days, the value of share declined by $1.00 , $1.75 and $1.50

$\bold{\underline{ To \: Find :- }}$

We have to find the value of a share of ABC stock at the end of 3 days

$\bold{\underline{ Let's \: Begin :- }}$

According to the question,

Cost of 1 share of ABC company = $18.75

Therefore, 

Cost of 140 shares purchased by Jan in the ABC company

$\sf{ = 140 × 18.75 }$

$\sf{ = 2625\: dollars }$

Now, 

For next 3 days, the value of share declined

$\sf{ = (1 + 1.75 + 1.50)dollars }$

$\sf{ = 4.25 \: dollars }$

Therefore, 

The value of shares after 3 days will be

$\bold{ = }{\bold{\frac{2625 - 4.25}{ 140}}}$

$\bold{ = }{\bold{\frac{ 2620.75}{ 140}}}$

$\bold{\red{ = 18.75\: dollars}}$

Hence, The value of share after 3 days will be $18.75 .

5 0

2 years ago

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th

finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

8 0

3 years ago