Answer:
Mg(s) + 2NaF (aq) —> MgF₂ (aq) + 2Na(s)
Explanation:
Magnesium => Mg
Sodium fluoride => NaF
Magnesium fluoride => MgF₂
Sodium metal => Na
The equation can be written as:
Mg + NaF —> MgF₂ + Na
Thus, the above equation can be balance as illustrated below:
Mg + NaF —> MgF₂ + Na
There are 2 atoms of F on the right side and 1 atom on the left side. It can be balance by writing 2 before NaF as shown below:
Mg + 2NaF —> MgF₂ + Na
There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 2 before Na as shown below:
Mg + 2NaF —> MgF₂ + 2Na
Mg(s) + 2NaF (aq) —> MgF₂ (aq) + 2Na(s)
Now, the equation is balanced.
<span>Persamaan setara pada reaksi besi dengan asam klorida membentuk besi (II) klorida dan gas hidrogen
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Answer:
The partial pressure of oxygen is 52 kPa.
Explanation:
We apply Dalton's law, according to which the sum of the partial pressures of the gases that make up a gaseous mixture is equal to the total pressure of this:
Ptotal = P N2 + P C02 + P 02
300 kPa= 200kPa + 48 kPa + P 02
P 02= 300 kPa - 200kPa - 48 kPa= <em>52 kPa</em>
Answer:
0.0928 grams of oxygen was collected.
Explanation:
Volume of oxygen gas collected = V= 75.3 mL = 0.0753 L (1 mL = 0.001 L)
Temperature of the gas = T = 25°C = 25+ 273 k = 298 K
Pressure of the gas = P - = 742 Torr - 24 Torr = 718 Torr
1 atm = 760 Torr
Moles of oxygen gas = n
Using an ideal gas equation;
n = 0.0029 mol
Mass of 0.0029 moles of oxygen gas :
0.0029 mol × 32 g/mol = 0.0928 g
0.0928 grams of oxygen was collected.
The answer is 1296.75 g
Molar mass of <span>Fe2(SO4)3 is the sum of atomic masses of its elements:
Mr(</span>Fe2(SO4)3) = 2Ar(Fe) + 3Ar(S) + 12Ar(O)
Ar(Fe) = 55.84 g/mol
Ar(S) = 32.06 g/mol
Ar(O) = 16 g/mol
Mr(Fe2(SO4)3) = 2 * 55.84 + 3 * 32.06 + 12 * 16
= 111.68 + 96.18 + 192
= 399.9 g/mol
Thus there are 399.9 g in 1 mol and x grams in 3.25 mol:
399 g : 1 mol = x : 3.25 mol
x = 399 g * 3.25 mol : 1 mol
x = 1296.75 g