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blondinia [14]
3 years ago
8

Determine the direction that each of the reactions will progress. Assume that the reactants and products are present in equimola

r amounts. The standard free energy of hydrolysis of ATP is – 30.5 kJ / mol.
Chemistry
1 answer:
xxMikexx [17]3 years ago
8 0

Answer:

It would move either left or right

Explanation: Taking assumption that,

Fructose + ATP fructose - 6 - phosphate + ADP (The standard free energy of hydrolysis for fructose-6-phosphate is - 15.9 kJ/mol.) 3 - phosphoglycerate + ATP 1,3 - bisphosphoglycerate + ADP (The standard free energy of hydrolysis for 1,3-bisphosphoglycerate is - 4 9.3 kJ/mol.) pyruvate + ATP phosphoenolpyruvate + ADP (The standard free energy of hydrolysis for phosphoenolpyruvate -is -61.9 kJ/mol.)

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Later when they are older

Explanation:

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2 years ago
What is the volume of a solid with a mass of 17.4 g and a density of 0.934 g /cm cubed?
Anvisha [2.4K]

Answer:

18.6 g/cm^3

Explanation:

17.4g/0.934g/cm^3

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5 0
3 years ago
When 100 mL of 1.0 M Na3PO4 is mixed with 100 mL of 1.0 M AgNO3, a yellow precipitate forms and [Ag ] becomes negligibly small.
lana [24]

Answer:

Na3PO4 + 3AgNO3 -------> Ag3PO4 + 3NaNO3

In which [Ag+] in negligibly small and the concentration of each reactant is 1.0 M

The answer is A)  PO43- < NO3- < Na+

Explanation:

Ag+ is removed from the solution just like PO43-, so there are just 2 possible answers at this point: a or b. Then we can notice that Na3PO4 releases 3 moles of Na+ and just 1 mole of NO3-

We have 100mL of each reactant with the same concentration for both (1.0 M) so:

(0.1)(1)(3)= 0.3 mol Na+

(0.1)(1)= 0.1 mol NO3-

so PO43- < NO3- < Na+

5 0
3 years ago
The process in which a gaseous substance is converted into a condensed, more usable chemical substance is called
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Single and double replacement reactions practice WS CuCl2 +<br> F2 »<br> CuF2<br> +<br> Cl2
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This is a single replacement because there is one compound and one element. Picture Cu as ‘A’ Cl2 as ‘B’ and F2 as ‘C.’ So AB+C—>AC+B. A and B “broke up” and that resulted to A going with C to create the compound CuF2 leaving Cl2 alone.
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