Nature of the solute and solvent - The amount of solute that dissolves depends on what type of solute it is. While only 1 gram of lead (II) chloride can be dissolved in 100 grams of water at room temperature, 200 grams of zinc chloride can be dissolved. This means that a greater amount of zinc chloride can be dissolved in the same amount of water than lead II chloride.
Temperature - Increasing the temperature not only increases the amount of solute that will dissolve but also increases the rate at which the solute will dissolve. For gases, the reverse is true. An increase in temperature decreases both solubility and rate of solution.
Pressure - Changes in pressure have practically no effect on solubility. For gaseous solutes, an increase in pressure increases solubility and a decrease in pressure decreases solubility. Example: When the cap on a bottle of soda pop is removed, pressure is released, and the gaseous solute bubbles out of solution. This escape of a gas from solution is called effervescence.
Stirring - Stirring brings fresh portions of the solvent in contact with the solute. Stirring, therefore, allows the solute to dissolve faster.
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The conversion factor that would be used to calculate the number of moles of Cl2 produced if 11 moles of HCl were present in the reaction is as follows:
4 mol HCl; 2 mol Cl2
<h3>How to calculate number of moles stoichiometrically?</h3>
The number of moles of a reactant or product of a reaction can be calculated using stoichiometry.
According to this question, the following balanced chemical reaction was given:
4HCl + O2 --> 2Cl2 + 2H2O
This reaction shows that 4 moles of HCl is required to produce 2 moles of Cl2, therefore, this is the conversion factor that would be used to calculate the number of moles of Cl2 if 11 moles of HCl was present.
Learn more about stoichiometry at: brainly.com/question/9743981
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Answer:
1.0 ° C
Explanation:
The molar mass for Sodium Nitrate NaNO₃ = (23+14+(16×3)) = 85
Number of moles of NaNO₃ = mass of NaNO₃ /molar mass of NaNO₃
⇒ 17/85 = 1.38 moles
Since 1 mole of NaNO₃ dissolved in 1 cubic decimeter of water, 40 kJ of heat energy is absorbed.
when 1.38 mole of NaNO₃ dissolved in 1 cubic decimeter of water, x kJ of heat energy is absorbed..
Then; x kJ of 1.38 mole of NaNo₃ = 1.38 × 40 kJ =55.2 kJ of heat absorbed.
Using the relation : Q = mcΔT to determine the temperature drop ; we get:
55.2 = 17 × 4 (ΔT)
55.2 = 68 ΔT
ΔT= 0.8 ° C
ΔT ≅ 1.0 ° C
Therefore, the drop in temperature when 17.0g of sodium nitrate is dissolved in 1 cubic decimeter of water is 1.0 ° C
Answer:
hypothesis
Explanation:
a question that can be answered wity a hypothesis is a question a scientist can answer
