Question

What volume of hydrogen gas is required to react with 113 liters of ethylene (C2H4) according to the following reaction? (All gases are at the same temperature and pressure.) hydrogen (g) + ethylene (C2H4) (g) ethane (C2H6) (g)

Answer 1

Answer: The volume of hydrogen gas required for the given amount of ethylene gas is 113 L

Explanation:

At STP:

1 mole of a gas occupies 22.4 L of volume

We are given:

Volume of ethylene = 113 L

For the given chemical equation:

$H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)$

By Stoichiometry of the reaction:

$(1\times 22.4)L$ of ethylene reacts with $(1\times 22.4)L$ of hydrogen gas

So, 113 L of ethylene gas will react with = $\frac{(1\times 22.4)}{(1\times 22.4)}\times 113=113L$ of hydrogen gas

Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L