Answer: if x is to the 2 power then
kx^2+12x-4=0 Add 4 to the both sides
kx^2+12x=4 Divide both sides by 12
kx^2=1/3x square root the both sides
k=0.6x
Step-by-step explanation:
U have to use Pythagoras theorem to solve this.. (adjacent)^2+(opposite)^2=hypotenuse^2
looking at the question,
the hypotenuse =15ft
opposite =12ft
adjacent =???
adjacent^2+(12)^2=15^2
a^2+144=225
group like terms
a^2=225-144
a^2=81
introduce square root to both side
root a^2=root81
a=9ft
therefore, the answer is 9ft.
3.8+7.6+9.3+31+43+54+62+89+107+119+123+127=775.7
775.7/12=64.64166666666667
So the mean is 64.64
For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
