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Kruka [31]
3 years ago
13

Complete the table for the equation. Then use the table to graph the equation.

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

Y goes like this: -3, -2, -1, 0, 1

Step-by-step explanation:

All you have to do is replace the X in the equation with the X in the chart.

For example, to find the first Y I just did:

y= -2-1

And whatever the thing equals is Y

Serggg [28]3 years ago
3 0
Multiply the x’s by -1 which would be 2,1,0,-1-2
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What is -5 plus -10 minus 41562 times 6
Citrus2011 [14]

Answer:

-249387

Step-by-step explanation:

1) Write out the problem

-5+-10-41562*6

2) Following order of operations, multiply -41562 by 6:

-5+-10-249372

3) Solve -5+-10:

-15-249372

4) Subtract:

-249387

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3 years ago
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Janice works at the We Are Cells. She earns $650 per week plus a 15% commission on all new cell phone contracts that she sells e
sertanlavr [38]

Answer:

y=650+15x

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4 years ago
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If A, B, and C are mutually exclusive events with P(A) 0.2, P(B): 0.3, and P(C) 0.4, determine the following probabilities:
Lesechka [4]

Answer:

a. 0.9

b. 0.024

c. 0.06

d. 0.2

e. 0.336

Step-by-step explanation:

Since A, B and C are mutually exclusive then P (A U B U C)=P(A)+P(B)+P(C) and P(A∩B∩C)=P(A)*P(B)*P(C).

a.

P (A U B U C)=P(A)+P(B)+P(C)

P (A U B U C)=0.2+0.3+0.4=0.9

b.

P(A∩B∩C)=P(A)*P(B)*P(C)

P(A∩B∩C)=0.2*0.3*0.4=0.024

c.

P(A∩B)=P(A)*P(B)

P(A∩B)=0.2*0.3=0.06

d.

P[(AUB)∩C]=P(AUB)*P(C)

P(AUB)=P(A)+P(B)=0.2+0.3=0.5

P[(AUB)∩C]=0.5*0.4=0.20

e.

P(A')=1-P(A)=1-0.2=0.8

P(B')=1-P(B)=1-0.3=0.7

P(C')=1-P(C)=1-0.4=0.6

P(A'∩B'∩ C')=P(A')*P(B')*P(C')

P(A'∩B'∩ C')=0.8*0.7*0.6=0.336

7 0
3 years ago
A petrol pump can hold enough petrol to supply 80
liberstina [14]
The answer is 56 cars because there is 2800 litres in the pump so if its 50 litres its going to be 2800/50=56
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