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jasenka [17]
3 years ago
13

Write an equation of the line in slope-intercept form that passes through (-3,5) and is perpendicular to y = -3x- 1

Mathematics
1 answer:
inna [77]3 years ago
6 0

9514 1404 393

Answer:

  y = 1/3x +6

Step-by-step explanation:

The slope of the given line is the coefficient of x, -3. The slope of the perpendicular line will be the opposite reciprocal of that:

  -1/(-3) = 1/3

The point-slope equation is then ...

  y -k = m(x -h) . . . . . for line of slope m through point (h, k)

Here, we have m = 1/3, (h, k) = (-3, 5), so the point-slope equation is ...

  y -5 = 1/3(x +3)

  y = 1/3x + 1 + 5 . . . . eliminate parentheses, add 5

  y = 1/3x +6 . . . . slope-intercept equation of the line

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AlekseyPX

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x = 24/6 = 4

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3 years ago
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Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

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4 years ago
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solmaris [256]

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According to statement

The given rates are 560, 468, 685, 534, 658, 593

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and use this formula S = sqrt [ X2 - n 2 / (n-1) ]

and put the values in these and

S = sqrt [ X2 - n 2 / (n-1) ] = 95.97179

So, The interval for mean sale price is $582

Learn more about SAMPLE MEAN here

brainly.com/question/16794295

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The domain is all x-values.

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Step-by-step explanation:

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