Answer:
p
Step-by-step explanation:
Answer:
I'm not going to give you the answer because you need to learn this on your own because it isn't hard.
Step-by-step explanation:
There are 4 main things you investigate in a number line: the median, the mode, the range, and mean. The median is the middle of your data set. You find the number of all of your data and find out the middle of that number. You find what line it is in on your data set. The range is the variety of numbers in your data set (for yours its 10). The mean is the average of your data set. The mode is the number that pops up the most (in your case, 2).
Answer:
<u>1. Mean = 342.7 (Rounding to the nearest tenth)</u>
<u>2. Median = 167.5 </u>
<u>3. Mode = There isn't a mode for this set of numbers because there isn't a data value that occur more than once. </u>
Step-by-step explanation:
Given this set of numbers: 107, 600, 115, 220, 104, 910, find out these measures of central tendency:
1. Mean = 107 + 600 + 115 + 220 + 104 + 910/6 = <u>342.7</u> (Rounding to the nearest tenth)
2. Median. In this case, we calculate it as the average between the third and the fourth element, this way:
115 + 220 =335
335/2 = <u>167.5 </u>
3. Mode = <u>There isn't a mode for this set of numbers because there isn't a data value that occur more than once. All the data values occur only once.</u>
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
A regular dodecahedron is a regular polyhedron composed of 12 equally sized regular pentagons.
