Answer:
1. 1/4
2. -3
3. 3
4. -3/2
5. -2
6. -3/4
Step-by-step explanation:
The roots of the given polynomials exist
, and
.
<h3>What is the formula of the quadratic equation?</h3>
For a quadratic equation of the form
the solutions are
![$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$](https://tex.z-dn.net/?f=%24x_%7B1%2C2%7D%3D%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E%7B2%7D-4%20a%20c%7D%7D%7B2%20a%7D%24)
Therefore by using the formula we have
![$x^{2}-16 x+54=0$$](https://tex.z-dn.net/?f=%24x%5E%7B2%7D-16%20x%2B54%3D0%24%24)
Let, a = 1, b = -16 and c = 54
Substitute the values in the above equation, and we get
![$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$](https://tex.z-dn.net/?f=%24x_%7B1%2C2%7D%3D%5Cfrac%7B-%28-16%29%20%5Cpm%20%5Csqrt%7B%28-16%29%5E%7B2%7D-4%20%5Ccdot%201%20%5Ccdot%2054%7D%7D%7B2%20%5Ccdot%201%7D%24%24)
simplifying the equation, we get
![$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\](https://tex.z-dn.net/?f=%24%26x_%7B1%2C2%7D%3D%5Cfrac%7B-%28-16%29%20%5Cpm%202%20%5Csqrt%7B10%7D%7D%7B2%20%5Ccdot%201%7D%20%5C%5C)
![$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\](https://tex.z-dn.net/?f=%24%26x_%7B1%7D%3D%5Cfrac%7B-%28-16%29%2B2%20%5Csqrt%7B10%7D%7D%7B2%20%5Ccdot%201%7D%2C%20x_%7B2%7D%3D%5Cfrac%7B-%28-16%29-2%20%5Csqrt%7B10%7D%7D%7B2%20%5Ccdot%201%7D%20%5C%5C)
![$&x=8+\sqrt{10}, x=8-\sqrt{10}](https://tex.z-dn.net/?f=%24%26x%3D8%2B%5Csqrt%7B10%7D%2C%20x%3D8-%5Csqrt%7B10%7D)
Therefore, the roots of the given polynomials are
, and
.
To learn more about quadratic equations refer to:
brainly.com/question/1214333
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Answer:
![z= \frac{3.44-2.54}{0.45}=2](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B3.44-2.54%7D%7B0.45%7D%3D2)
![P(X>3.44) = P(Z>2) = 0.025](https://tex.z-dn.net/?f=%20P%28X%3E3.44%29%20%3D%20P%28Z%3E2%29%20%3D%200.025)
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the grade points avergae of a population, and for this case we know the following properties
Where
and
The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).
So we can find the z score for the value of X=3.44 in order to see how many deviations above or belowe we are from the mean like this:
![z= \frac{3.44-2.54}{0.45}=2](https://tex.z-dn.net/?f=%20z%3D%20%5Cfrac%7B3.44-2.54%7D%7B0.45%7D%3D2)
So the value of 3.44 is 2 deviations above from the mean, so then we know that the percentage between two deviations from the mean is 95% and on each tail we need to have (100-95)/2 = 2.5% , because the distribution is symmetrical, so based on this we can conclude that:
![P(X>3.44) = P(Z>2) = 0.025](https://tex.z-dn.net/?f=%20P%28X%3E3.44%29%20%3D%20P%28Z%3E2%29%20%3D%200.025)
Answer:
118%
Step-by-step explanation:
Cora's kitten weighed in the last visit to the veterinarian's office= 550 grams
Right now, Cora's kitten weighs = 1200 grams
Increase in the kitten's weight= 1200 - 550 = 650 grams
Percent increase in weight= 650/550 * 100
= 118.18% = 118%
Hence, there is 118% increase in kitten's weight.
1/9 pints of milk can be added by a customer
Step-by-step explanation:
We have to subtract simple fractions to find the amount of milk that can be added to a cup of coffee
Given
Total Capacity of a cup = 7/9 pints
Coffee to be added in a cup = 2/3 pints
So in order to find the amount of milk that can be added we have to subtract the amount of coffee from the total capacity of cup.
So,
![Amount\ of\ milk = \frac{7}{9} - \frac{2}{3}\\=\frac{7-6}{9} = \frac{1}{9}](https://tex.z-dn.net/?f=Amount%5C%20of%5C%20milk%20%3D%20%5Cfrac%7B7%7D%7B9%7D%20-%20%5Cfrac%7B2%7D%7B3%7D%5C%5C%3D%5Cfrac%7B7-6%7D%7B9%7D%20%3D%20%5Cfrac%7B1%7D%7B9%7D)
Hence,
1/9 pints of milk can be added by a customer
Keywords: Fractions, addition
Learn more about fractions at:
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