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3 years ago

Find a26 of the sequence-2,-8,-14,-20

Mathematics

1 answer:

ddd [48]3 years ago

4 0

The numbers decrease by 6.

-1, -8, -14, -20, -26, -32, -38, -44, -50, -56, -62, -68, -74, -80, -86, -92, -98, -104, -110, -116, -122, -128, -134, -140, -146

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Find 4.23 - 6.87 Write your answer as a decimal

patriot [66]

Answer:

-2.64

Step-by-step explanation:

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3 years ago

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Express the product of 3/8 x 4/9 in simplest form

NeX [460]

When multiplying fractions, you multiply the denominators together and the numerators together.
3/8 x 4/9
(4•3)/(8•9)
12/72 = 1/6

1/6 is the final answer.

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3 years ago

Consider the differential equation x^2 y''-xy'-3y=0. If y1=x3 is one solution use redution of order formula to find a second lin

Anastasy [175]

Suppose $y_2(x)=y_1(x)v(x)$ is another solution. Then

$\begin{cases}y_2=vx^3\\{y_2}'=v'x^3+3vx^2//{y_2}''=v''x^3+6v'x^2+6vx\end{cases}$

Substituting these derivatives into the ODE gives

$x^2(v''x^3+6v'x^2+6vx)-x(v'x^3+3vx^2)-3vx^3=0$

$x^5v''+5x^4v'=0$

Let $u(x)=v'(x)$ , so that

$\begin{cases}u=v'\\u'=v''\end{cases}$

Then the ODE becomes

$x^5u'+5x^4u=0$

and we can condense the left hand side as a derivative of a product,

$\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0$

Integrate both sides with respect to $x$ :

$\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C$

$x^5u=C\implies u=Cx^{-5}$

Solve for $v$ :

$v'=Cx^{-5}\implies v=-\dfrac{C_1}4x^{-4}+C_2$

Solve for $y_2$ :

$\dfrac{y_2}{x^3}=-\dfrac{C_1}4x^{-4}+C_2\implies y_2=C_2x^3-\dfrac{C_1}{4x}$

So another linearly independent solution is $y_2=\dfrac1x$ .

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3 years ago

What is the area of the square? A square with the left side labeled 4 units.

Liono4ka [1.6K]

Area of square is a^2
4^2 = 16
the area is 16 units

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2 years ago

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Why does the fact family for 81 and 9 have only two number sentences

Julli [10]

It only has two number sentences because 81 divided by anything else wont work only 9 would. Also since 9 times 9 is equal to 81

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3 years ago

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