Answer:
Option 1.1
Step-by-step explanation:
The linearization of a curve implies the use of calculus to find the local value for the derivative and approximating the function by the use of the formula
The function is given in such way that it's much easier to find the derivative by implicit differentiation than isolating any of the variables
Differentiating with respect to x, we have
Computing y' in the given point (3,1) we have
4(3)(1)+2(9)y'+y'=2
The function will be approximated with the expression
To find the approximate value for x=2.8
The correct value is the option 1.1
Ok so first we find the equation that equals one variable.
2y = -x + 9
3x - 6y = -15
We solve for y.
2y = -x + 9
y = -x/2 + 9/2
Then we plug in this y value into the other equation to keep only one variable so we can solve for it.
3x - 6y = -15
3(-x + 9/2) - 6y = -15
-3x + 27/2 - 6y = -15
-9y + 27/2 = -15
-9y = 3/2
-y = 3/18
y = -3/18
Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.
y = -x/2 + 9/2
-3/18 = -x/2 + 9/2
-84/18 = -x/2
-x = 9 1/3
x = -28/3
Your answer would be (-28/3, -3/18)
Hope this helps!
Answer:
y=4
Step-by-step explanation:
From the graph we can see that-
when, x=-3 , y=4
That is , the graph passes through (-3 , 4)
So,
for x=-3 ,
we get y=4
So, the answer is y=4
B is the answer because you have to math it
