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3 years ago

Can someone be my tutor I really need some help :)

Mathematics

1 answer:

weeeeeb [17]3 years ago

8 0

Answer:

depends on what you need helps with

have a good day :)

Step-by-step explanation:

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Ax+c=r Solve for x<br> Need help can anybody help?

kkurt [141]

What are the numbers for the other ones?

4 0

4 years ago

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Find the larger of the two roots of the equation y = -2.2x2 + 63.5x - 17

Luden [163]

The larger of the two roots of the equation $y = -2.2x^2 + 63.5x - 17$ would be 28.59.

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is

$ax^2 + bx + c = 0$

Then its roots are given as:

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

The given quadratic equation is

$y = -2.2x^2 + 63.5x - 17$

now, the roots of the equation are

$x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}$

The two roots are 0.27 and 28.59.

Thus, the larger of the two roots of the equation $y = -2.2x^2 + 63.5x - 17$ would be 28.59.

Learn more about finding the solutions of a quadratic equation here:

brainly.com/question/3358603

#SPJ1

7 0

2 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

6 0

3 years ago

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How many ways can Gary, Cayla, and

Kryger [21]

Answer:

Step-by-step explanation:

G,C,P

C,P,G

P,G,C

G,P,C

P,C,G

C,G,P

4 0

4 years ago

A community is building a square park with sides that measure 150 meters. To separate the picnic

Firlakuza [10]

Answer:

212 meters

Step-by-step explanation:

The diagonal of a square is the square root of 2 times the length of the square. This can be rewritten as the square root of (2*area)

2 * 22500 = 45000

The square root of 45000 is about 212.13, which would round down to 212 meters.

7 0

3 years ago