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Which statement accurately describes covalent bonds

DaniilM [7]

Options are as follow,

A) Covalent bonds are formed by metals and nonmetals.
B) Covalent bonds are are typical of carbon compounds.
C) Covalent bonds are created by the attractions between oppositely charged ions.
D) Covalent bonds break apart when dissolved in water and allow for the conduction of electricity.

Answer:
Covalent bonds are formed by mutual sharing of electrons between two atoms of having electronegativity difference less than 1.7. Among given options only option-B seems correct.

Explanation:
Carbon containing compounds are almost covalent in nature. Majority of organic compounds are made up of carbon, hydrogen, oxygen and nitrogen. And carbon makes covalent bonds with all these atoms.

Result:
Option-B is correct.

8 0

3 years ago

Several properties of the element magnesium are shown. Which one is a chemical property?

aniked [119]

Answer:

E

Explanation:

burning a substance changes it chemically.

4 0

3 years ago

Determine the acid dissociation constant for a 0.020 m formic acid solution that has a ph of 2.74. formic acid is a weak monopro

Setler [38]

Answer:

Ka = 1.82x10⁻⁴

Explanation:

To solve this problem, we need a basis. In this case, we need the overall reaction and a ICE chart. So, let's write the overall reaction first:

HCOOH + H₂O <--------> H₃O⁺ + HCOO⁻ Ka = ?

Now that we have the overall reaction, we need to write the ICE chart. In this way we can determine what data do we have, and what do we have left to determine:

HCOOH + H₂O <--------> H₃O⁺ + HCOO⁻ Ka = ?

i) 0.02 0 0

e) 0.02-x x x

The Ka expression is:

Ka = [H₃O⁺] [HCOO⁻] / [HCOOH]

Replacing the given data we have:

Ka = x² / 0.02 - x

Now, the value of x can be calculated because we already have the pH of the formic acid, and with it, we can calculate the [H₃O⁺] with the following expression:

[H₃O⁺] = 10^(-pH)

Replacing we have:

[H₃O⁺] = 10^(-2.74) = 1.82x10⁻³ M

This is the value of x, so replacing in the Ka expression, we can calculate then, the value of Ka:

Ka = (1.82x10⁻³)² / (0.02 - 1.82x10⁻³)

7 0

3 years ago

A student prepares a aqueous solution of trimethylacetic acid . Calculate the fraction of trimethylacetic acid that is in the di

irinina [24]

The question is incomplete, here is the complete question:

A student prepares a 0.21 mM aqueous solution of trimethylacetic acid. Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 3 significant digits.

Answer: The percent of dissociation of trimethylacetic acid is 19.5 %

Explanation:

We are given:

Concentration of trimethylacetic acid = 0.21 mM = 0.00021 M (Conversion factor: 1 mole = 1000 millimoles )

The chemical equation for the dissociation of trimethylacetic acid follows:

$C_4H_9COOH\rightleftharpoons C_4H_9COO^-+H^+$