Question

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g sucrose in 1.75 L solution?

Answer 1

0.5/1.75 = 0.285 M Hope this helps

Answer 2

Answer: The molarity of sucrose solution is 0.286 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

We are given:

Mass of solute (sucrose) = 171 g

Molar mass of sucrose = 342 g/mol

Volume of solution = 1.75 L

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{171g}{342g/mol\times 1.75L}\\\\\text{Molarity of solution}=0.286M$

Hence, the molarity of sucrose solution is 0.286 M