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babymother [125]
3 years ago
15

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g suc

rose in 1.75 L solution?
Chemistry
2 answers:
Andrew [12]3 years ago
7 0
<span>0.5/1.75 = 0.285 M Hope this helps</span>
Ganezh [65]3 years ago
7 0

<u>Answer:</u> The molarity of sucrose solution is 0.286 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

We are given:

Mass of solute (sucrose) = 171 g

Molar mass of sucrose = 342 g/mol

Volume of solution = 1.75 L

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{171g}{342g/mol\times 1.75L}\\\\\text{Molarity of solution}=0.286M

Hence, the molarity of sucrose solution is 0.286 M

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