A girl has 11 coins in dimes and quarters. Their value is $1.55. How many quarters does she have?

(5n - 3) - (-2n + 7)

AleksandrR [38]

Answer:

7n-10

Step-by-step explanation:

=(5n-3) - (-2n) -7 [Bracket Opens]

=5n - 3 +2n -7 [- × - = +]

=7n - 10 [ addition]

4 0

2 years ago

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.261$

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.369$

And the 90% confidence interval would be given (0.261;0.369).

We are confident at 90% that the true proportion of people that they were planning to pursue a graduate degree is between (0.261;0.369).

lower limit =0.261

upper limit =0.369

5 0

3 years ago

What is the probability that a student eye color would be blue if their grade in physics is A? A two way table is presented belo

Zarrin [17]

The <u>correct answer</u> is:

16/45.

Explanation:

We want the probability that a student's eye color is blue if they made an A in physics. This means we look at the column for students with an A.

There are 32 students with blue eyes in the A column.

This is out of 32+58=90 students that made an A.

This makes the probability 32/90, which simplifies to 16/45.

8 0

2 years ago

A rectangular driveway is 47ft long and 19 feet wide. whats its perimeter

Diano4ka-milaya [45]

Answer:

132ft

Step-by-step explanation:

add all the sides

47+47+19+19=132

3 0

3 years ago

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