Answer:
<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>
Step-by-step explanation:
Here are the steps to solve this equation:
<u>Given:</u>
First step: 2(y+6)-4y
Use the distributive property.
<u>Distributive property:</u>
<h3>
⇒ A(B+C)=AB+AC</h3>
2(y+6)
2*y=2y
2*6=12
2y+12
Isolate the term of y from one side of the equations.
2y+12=4y
Subtract by 12 from both sides.
2y+12-12=4y-12
Solve.
2y=4y-12
Then, you subtract by 4y from both sides.
2y-4y=4y-12-4y
Solve.
2y-4y=-2y
-2y=-12
Divide by -2 from both sides.

Solve.
Divide the numbers from left to right.
<u>Solutions:</u>
-12/-2=6

- <u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>
I hope this helps. Let me know if you have any questions.
Ok so assuming the 0 means minus from typing problems
x^2-10x=-8
to completet the square
make sure the term in front of x^2 is 1
that is correct
then take 1/2 of the term in front of the x term and square it
-10/2=-5, (-5)^2=25
add that to both sides
x^2-10x+25=17
answer is the first equation