A zookeeper took a random sample of 30 days and observed how much food an elephant ate on each of those days. The sample mean wa
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Answer:
The population of bacteria can be expressed as a function of number of days.
Population = where n is the number of days since the beginning.
Step-by-step explanation:
Number of bacteria on the first day=
Number of bacteria on the second day =
Number of bacteria on the third day =
Number of bacteria on the fourth day =
As we can see , the number of bacteria on any given day is a function of the number of days n.
This expression can be expressed generally as where n is the number of days since the beginning.
Answer:
The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution should be used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 28 - 1 = 27
80% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 27 degrees of freedom(y-axis) and a confidence level of . So we have T = 1.314
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 34.6 - 0.646 = $33.954
The upper end of the interval is the sample mean added to M. So it is 34.6 + 0.646 = $35.246
The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.