A simple random sample of 25 filtered 100 mm cigarettes isobtained, and the tar content of each cigarette is measured. The samp
le has a mean of 19.4 mg and a standard deviation of 3.23 mg. Use a 0.05 significance level to test the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg, which is the mean for unfiltered king size cigarettes.Please select all TRUE statements from those givem below.1. For this hypothesis test the P-value = .0072. There is sufficient evidence to support the claim that the mean tar content of filtered 100 mm cigarettes is less than21.1 mg.3. For this hypothesis test; H0; 1.1 H1: 21.14. For this hypothesis test the test statistic is t = -2.6325. service.php?service=cache&name=55e1f2083
We know that Ava is paying $2 dollars per week so if L is the money that she owes and t is the number of weeks, and I is the initial debt so we can write an equation like:
Now we can replace the info we have to find the value of I so:
Area of the garden that 15 trees are planted will be: Area=250×25=6250 ft² but 1 acre= 43560 ft² thus converting our area to acres we get: 6250/(43560) =0.1435 acres thus the population density will be: (Population)/(area) =15/0.1435 =104.544 trees/acre
