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MArishka [77]
3 years ago
6

A simple random sample of 25 filtered 100 mm cigarettes is​obtained, and the tar content of each cigarette is measured. The samp

le has a mean of 19.4 mg and a standard deviation of 3.23 mg. Use a 0.05 significance level to test the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 ​mg, which is the mean for unfiltered king size cigarettes.Please select all TRUE statements from those givem below.1. For this hypothesis test the P-value = .0072. There is sufficient evidence to support the claim that the mean tar content of filtered 100 mm cigarettes is less than21.1 mg.3. For this hypothesis test; H0; 1.1 H1: 21.14. For this hypothesis test the test statistic is t = -2.6325. service.php?service=cache&name=55e1f2083
Mathematics
1 answer:
qwelly [4]3 years ago
5 0

Answer:

h0:u ≥ 21.1

h1: u < 21.1

t statistics = -2.632

pvalu = 0.007

there is sufficient evidence to support claim

Step-by-step explanation:

null hypothesis

h0 = u≥21.1

alternative = u < 21.1

to get test statistics

barx - u / s/√n

= 19.4 - 21.1 / 3.23/√25

= -2.632

we calculate for the p value given this test statistics and the degree of freedom = 25-1 = 24

lest tailed p value = 0.0073 this is approximately 0.007

p value is less than the level of significance so we reject h0

we conclude that we have enough evidence to support h1, mean tar conent is less than 21.1

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Read 2 more answers
Solve by using any method of substitution<br><br>4 +8x = y <br>6x - y = 2
Bumek [7]

Answer:

(-3,-20)

Step-by-step explanation:

4 +8x = y ...... equation (1)

6x - y = 2 ........equation(2)

from equation 2

6x - y = 2

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