Answer:
Step-by-step explanation:
From the picture attached,
a). Triangle in the figure is ΔBCF
b). Since,
and
are the parallel lines and m is a transversal line,
m∠FBC = m∠BFG [Alternate interior angles]
Since,
and
are the parallel lines and n is a transversal line,
m∠BCF = m∠CFE [Alternate interior angles]
By triangle sum theorem in ΔBCF
m∠FBC + m∠BCF + m∠BFC = 180°
From the properties given above,
m∠BFG + m∠CFE + m∠BFC = 180°
m∠GFE = 180°
Therefore, angle GFE is the straight angle that will be useful in proving that the sum of the measures of the interior angles of the triangle is 180°.
Answer:
2 pairs of opposite parallel sides is parallelogram
Just move over each of those points to theme right 3 and down 7 then connect the dots again
Answer:
9 units
Center is at (5, 0)
Step-by-step explanation:
The radius of the circle is equal to the square root of 81
= ±9
Since the radius of a circle must be positive the answer is 9 units.
The center of the circle is at (5, 0)
Answer: Option D

Step-by-step explanation:
For a quadratic function of the form

The x coordinate of the vertice is:

In this case the function is:

So

The x coordinate of the vertice is:

The y coordinate of the vertice is:

The vertice is: (-3, -11)
The form e vertice for a quadratic equation is:

Where
the x coordinate of the vertice is h and the y coordinate of the vertice is k.
Then h=-3 and k =-11
Finally the equation
in vertex form is:
