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3 years ago

Which figures will have a volume that is greater than 100 cubic units? Select two options.

Mathematics

1 answer:

andrey2020 [161]3 years ago

4 0

I think that it is b. A rectangular prism with dimensions of 2 by 12

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ONCE I HIT 30 ILL GIVE YOU 100 Points if i get a good grade Maybe even more

N76 [4]

Answer:

The correct anwser is 2x+5<4

Step-by-step explanation:

8 0

3 years ago

Write and solve a proportion to answer the question. (Skills Review Handbook) 22. 30 is 15% of what number?

algol13

Answer:

The answer is 148.6666667

Step-by-step explanation:

1) Set a linear quation

$\frac{22.30}{x} = \frac{15}{100}$

2) Cross multiply

$15x = 22.30 \times 100$

3) Multiple the right side

$15x = 2230$

4) Divide both side by 15

$\frac{15x}{15} = \frac{2230}{15}$

5) Solve the linear equation

$x = 148.6666667$

3 0

2 years ago

Which pair of data sets would most likely have no correlation?

kaheart [24]

Answer:

The first one is correct.

Hope this helps

Mark me brainliest if I'm right :)

7 0

3 years ago

Alona [7]

Based on the coordinates of triangle RST, we can infer that triangle RST is <u>not a right-angled triangle. </u>

<h3>Is triangle RST a right-angled triangle?</h3>

For this to be a right-angled triangle, the Pythagoras theorem has to apply where:

Largest side² = Side A² + Side B²

Lengths of the triangle:

RS² = (4 - 2)² + (4 - 3)²

= 5

ST² = (5 - 4)² + (0 - 9)²

= 17

TR² = (2 - 5)² + (3 - 0)²

= 18

We can see that:

18 ≠ 17 + 5

This is therefore not a right-angled triangle.

Find out more on the Pythagoras theorem at brainly.com/question/343682.

#SPJ9

6 0

2 years ago

Read 2 more answers

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 m

rusak2 [61]

Answer:

0.59375

Step-by-step explanation:

In a uniform distribution the probability that the time t is greater than any given value, X, is:

$P(t\geq X)=1-\frac{X}{b-a}$

In this problem, the limits of the distribution are a = 0 and b = 8 minutes.

For X =3.25 minutes:

$P(t\geq 3.25)=1-\frac{3.25}{8-0} \\P(t\geq 3.25)=0.59375$

The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is 0.59375.

8 0

3 years ago