Rewriting the question, the given lengths that were cut from the board were 30 3/4 inches, 12 1/4 inches, and 16 1/4 inches. To obtain the remaining length of the board, all of the measurements cut are to be added and subtracted from 72 inches. This is shown below:
30 3/4 + 12 1/4 + 16 1/4 = 237/4 = 59.25 inches.
Remaining length of board = 72 - 59.25 = 12.75 inches.
Therefore, there will be 12.75 inches remaining of the board.
Answer:
21
Step-by-step explanation:
27÷3 is 9 and 21÷3 is 7
So you have to add all the numbers to get the perimeter or the outside distance but it looks like t and s is there a few times so that’s were you have to simplify.
So here’s the answer simplified
4t+2s+w+v+x+u
Good luck!
Answer:
Height of second tower = 17.32m
Step-by-step explanation:
I have attached a diagram depicting the question.
From the diagram, The first tower is depicted by side AEB and the second tower CD.
While d is the distance that separates the two towers and it's given as 15m.
Now, since the angle of depression of the second tower’s base is 60°, then for triangle BAC. Angle C = 60°.
Thus; using trigonometric ratios;
tan 60° = AB/AC.
This gives; AB = d*tan 60°
Similarly, for the triangle BED, BE = d*tan 30°
Since, AE = CD, thus ;
CD = AB − BE
CD = d (tan 60° − tan 30°)
CD = 15(1.7321 − 0.5774)
CD = 15 × 1.1547
CD ≈ 17.32 m.
So, height of second tower = 17.32 m
3x^2 - 8x + 5
3x^2 - 3x - 5x + 5
3x(x - 1) - 5(x - 1)
(x - 1)(3x - 5)
The answer is: (x - 1)(3x - 5).