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vaieri [72.5K]
3 years ago
8

Plz help I’m getting timed

Mathematics
2 answers:
Ratling [72]3 years ago
7 0

Answer:

rhombus

Step-by-step explanation:

Fed [463]3 years ago
6 0

id say its a rhombus. all the other shapes can have right angles

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The average number of tunnel construction projects that take place at any one time in a certain state is 3. Find the probability
slega [8]

Answer: 0.1008188

Step-by-step explanation:

The question will usng the poisson distribution formula:

Given :

Mean(λ) number of occurrence in a given interval = 3

P(X=x) = Probability of exactly x occurrence in a given interval

Number of desired occurence(x) = 5

P(X=x) = [(λ^x) * (e^-λ)] / x!

Where ; e = base of natural logarithm = 2.7182818

P(X=5) = [(3^5) * (e^-3)] / 5!

P(X=5) = [(243) * (0.0497870)] / 120

P(X=5) = [12.098257] / 120

P(X=5) = 0.1008188

6 0
3 years ago
globe has a diameter of 12 inches. What is the volume of the globe? Use 3.14 for pi. Round your answer to the nearest hundredth
vesna_86 [32]
113.09 because you divide the 12 by two because the rule 

4 0
3 years ago
Read 2 more answers
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}

In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

6 0
3 years ago
Solve 1/p+1/s=1 for p
jekas [21]

Answer:

Step-by-step explanation:

Multiply through by the L. C. M which is PS.

1/p*ps+1/s*ps=1*ps

P+p=ps

2p=ps

Divide both sides by 2

2p/2=ps/2

P=ps/2

3 0
3 years ago
ILL BRAINLIEST YOU PLEASE HELP ME
Aleksandr-060686 [28]

Answer:

x = 71/5  (as an improper fraction)

x = 14 1/5 (as a proper fraction

x = 14.2 (as a decimal)

Step-by-step explanation:

It's a rectangle so the diagonals are equal

7x - 9 = 2x + 62

Subtract 2x from both sides

5x - 9 = 62

Add 9 to both sides

5x = 71

Divide both sides by 5

x = 71/5  (as an improper fraction)

x = 14 1/5 (as a proper fraction

x = 14.2 (as a decimal)

8 0
2 years ago
Read 2 more answers
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