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3 years ago

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Mathematics

1 answer:

Tju [1.3M]3 years ago

3 0

This fjzbwndjsjenskfkfnf I’m dababy

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56 divided by 7 jdjcjdjdjdjfjjfhfjfhfjfhfufgdjssgjsjshsjwiwh

mrs_skeptik [129]

Its 8.

_08___
7 / 56
56
-----------------
0 <--- Leftover

So the answer is 8! Hope it helps! :D

6 0

3 years ago

Find the product:<br> (-9)(-4)

nadya68 [22]

Answer:

Step-by-step explanation:

-9*-4=36

3 0

3 years ago

25 Points Please help!!!!

LenKa [72]

Answer:

i cant really see the picture

Step-by-step explanation:

try the app that you scn math math woks and it gives you the answer

3 0

3 years ago

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/

VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

$A = \frac{1}{2}bh$ (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

$\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)$

We can find the base by solving equation (1) for b:

$b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm$

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

$2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)$

$\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min$

Therefore, the base is decreasing at 2 cm/min.

I hope it helps you!

7 0

2 years ago

Suppose a researcher is interested in understanding the variation in the price of store brand milk. A random sample of 36 grocer

liberstina [14]

Answer: ($3.055, $3.205)

Step-by-step explanation:

Given : Significance level : $\alpha: 1-0.95=0.5$

Critical value : $z_{\alpha/2}=1.96$

Sample size : n= 36

Sample mean : $\overline{x}=\$\ 3.13$

Standard deviation : $\sigma= \$\ 0.23$

The confidence interval for population mean is given by :_

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

$\text{i.e. }\$\ 3.13\pm (1.96)\dfrac{0.23}{\sqrt{36}}\\\\\approx\$\ 3.13\pm0.075\\\\=(\$\ 3.13-0.075,\$\ 3.13+0.075)=(\$\ 3.055,\$\ 3.205)$

Hence, the 95% confidence interval to estimate the population mean = ($3.055, $3.205)

3 0

3 years ago