now, there are 1000 grams in one Kilogram, so in 1680 grams, there are 1680/1000 Kilograms, namely 1.680.
Answer:
Step-by-step explanation:
24√3
5
where are you people getting these like lol
Answer:
Hi there!
Your answer is;
a)
i) 400% of 240
240 is 100%
× 4
960= 400%
ii) 40% of 240
100% = 240
/100
1% = 2.4
× 40
40% = 96
iii) 4% of 240
100% is 240
/100
1% = 2.4
× 4
4% = 9.6
iv) .04% of 240
100% = 240
/100
1% = 2.4
/100
.01% = .024
× 4
.04% = .096
b) the patterns is that all these numbers equal sometime 96. Each of these have a different decimal place, but have the same actual numbers.
c) 4000% = 240
take the pattern:
400% is 960
Scale it up to 4000 by 10
400% is 960
× 10
4000% is 9600
Hope this helps!
Answer:
a. 25.98i - 15j mi/h
b. 1.71i + 4.7j mi/h
c. 27.69i -10.3j mi/h
Step-by-step explanation:
a. Identify the ship's vector
Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h
Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h
b. Identify the water current's vector
Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h
Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h
c. Identify the vector representing the ship's actual motion.
The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.
V = v + v'
= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h
= (25.98i + 1.71i + 4.7j - 15j )mi/h
= 27.68i -10.3j mi/h
