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Vladimir [108]
4 years ago
7

PLEASE I NEED AN ANSWER ASAP! THANK YOU.

Mathematics
2 answers:
Brrunno [24]4 years ago
8 0
D....the empty weight is 160gr
Kisachek [45]4 years ago
4 0

Answer:

D.  

The y-intercept of the line means that the weight of the empty jar is about 160 grams.


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What is the area of the trapezoid to the nearest tenth? <br> PICTURE BELOW ⬇⬇⬇⬇
Nastasia [14]

Answer:

  62.4 ft²

Step-by-step explanation:

The unmarked horizontal dimension at the bottom of the triangle is ...

  (8 ft)sin(30°) = 4 ft

The unmarked vertical dimension of the triangle (the height of the trapezoid) is ...

  (8 ft)cos(30°) ≈ 6.93 ft

Then the area of the trapezoid is given by the formula ...

  A = (1/2)(b1 +b2)h

  A = (1/2)((4 ft+7 ft) +(7 ft))(6.93 ft) ≈ 62.4 ft²

_____

The mnemonic SOH CAH TOA can remind you of the relationships between right triangle dimensions and angles.

  Sin = Opposite/Hypotenuse   ⇒   Hypotenuse×Sin = Opposite

  Cos = Adjacent/Hypotenuse   ⇒   Hypotenuse×Cos = Adjacent

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3 years ago
Convert the quadratic equation, <br>f (x) = 2(x - 3)2 +1, into standard form.​
laiz [17]

Step-by-step explanation:

........4x-y=11........

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3 years ago
Your class is selling wrapping paper and candles. Rolls of paper sell for $7 and candles sell for $10 each. A total of 109 items
Klio2033 [76]

Answer:

53 Rolls of paper and 56 Candles

Step-by-step explanation:

56 x $10 = $560

$7 x 53 = $371

$560 + $371 = $931

And 56 candles sold plus 53 rolls of paper sold equals 109 items sold

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3 years ago
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Standard algorithm for multiplication
Oksi-84 [34.3K]
A standard algorithm is a step-by-step way to solve a problem.

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3 years ago
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What is the maximum area for a rectangle whose perimeter is 48 meters?
MakcuM [25]

Answer:

12m²

Step-by-step explanation:

For a rectangle, with length L and width W,

the perimeter is given as

Perimeter,

P = (2 x Length)  + (2 x Width)

P = 2L + 2W

It is given that the perimeter is 48, hence

48 = 2L + 2W   (divide both sides by 2)

24 = L + W

or

L = 24 - W -----> eq 1

Also realize that the Area of a Rectangle is given by

A = L x W  -----> eq 2

Substituting eq 1 into eq 2,

A = (24 - W) x W

A = -W² + 24W

Recall that for a quadratic equation y = ax² + bx + c, the maxima or minima is given by y(max) =  -b/2a

In this case, b = 24 and a = -1

-b/2a = -24/[ 2(-1) ] = 12

Hence for A to be maximum A(max) = 12m² (Answer)

5 0
3 years ago
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