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3 years ago

NEED HELP ASAP PLEASE HELP

Chemistry

2 answers:

11Alexandr11 [23.1K]3 years ago

5 0

It is a why cause it doesn’t change color

ololo11 [35]3 years ago

3 0

Answer:

I think it's A not D or C maybe B probably A

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Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o

vivado [14]

Answer:

For 1: The amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2: The amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

Explanation:

For 1:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of $KIO_3$ solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

$0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol$

Hence, the amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2:

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = $\frac{1}{2}\times 0.00025=0.000125mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

6 0

3 years ago

How many molecules of he are contained in a 10.0 l tank at 7.53 atm and 485 k?

ankoles [38]

Answer:

1.126 x 10^22

Explanation:

pV = nRT

7.53 x 10 = n x 8.31 x 485

n = (7.53 x 10) / (8.31 x 485) = 0.0187 moles

M = n x Avogadros number

0.0187 x 6.02 x 10^23 = 1.126 x 10^22

4 0

3 years ago

HELP ASAP I WILL GIVE BRAINLIEST

alina1380 [7]

Answer:

it can last for 30 minutes

Explanation:

because it is very good at giving off heat, extothermal heat can last for quite a while.

3 0

3 years ago

Convert 5.4g of NaCl to moles

sammy [17]

Answer:

.0924 moles of NaCl

Explanation:

So you know you have 5.4 g of NaCl and you need to know how many moles there are in this amount of NaCl

You'll need to find the atomic mass of the compound NaCl to help you solve for moles

Sodium (Na) on the periodic table has a mass of 22.99

Chlorine (Cl) on the periodic table has a mass of 35.45

Add these two together----> 22.99 + 35.45 = 58.44

Now you can calculate for moles

Written-out method:

5.4 grams of NaCl | 1 mole of NaCl

| 58.44 grams NaCl = .0924 moles of NaCl

Plug into calculator method:

(5.4 g of NaCl/ 58.44g NaCl= .0925 moles)

7 0

3 years ago

What occurs when the nuclei of two very small atoms combine into one large nucleus?

Svetlanka [38]

Answer:

The combination of nuclei to form a bigger and heavier nucleus is known as Fussion. The consequence of fusion is the absorption or release of energy.

7 0

4 years ago